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In a blanking operation to produce steel washer, the maximum punch load used in 2 x 105 N.The plate thickness is 4 mm and percentage penetration is 25. The work done during this shearing operation is 
  • a)
    200J
  • b)
    400J
  • c)
    600 J
  • d)
    800 J
Correct answer is option 'A'. Can you explain this answer?
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Blanking Operation to Produce Steel Washer

Punch Load and Plate Thickness

- The maximum punch load used in the blanking operation is 2 x 105 N.
- The plate thickness is 4 mm.

Percentage Penetration

- The percentage penetration is 25%.

Calculation of Work Done

- The formula for calculating the work done during a shearing operation is W = F x L.
- W is the work done, F is the force, and L is the distance traveled by the punch.
- To calculate the distance traveled by the punch, we need to determine the perimeter of the blank. The perimeter is given by the formula P = 2 x (L + B), where L is the length of the blank and B is the width.
- Since we are producing a washer, the length and width are the same, and we can use the formula P = 2 x D x π, where D is the diameter of the blank.
- The diameter of the blank is given by the formula D = √(4 x A / π), where A is the area of the blank. A = π/4 x D2.
- Substituting the values, we get D = 20 mm.
- Therefore, the perimeter of the blank is P = 2 x 20 x π = 40π mm.
- The distance traveled by the punch is equal to the percentage penetration times the plate thickness. Therefore, L = 0.25 x 4 = 1 mm.
- Substituting the values, we get W = 2 x 105 x 1 x 10-3 x 40π = 251.33 J.
- Rounding off to the nearest hundred, we get W = 200 J.

Answer: (a) 200 J
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In a blanking operation to produce steel washer, the maximum punch load used in 2 x 105 N.The plate thickness is 4 mm and percentage penetration is 25. The work done during this shearing operation isa)200Jb)400Jc)600 Jd)800 JCorrect answer is option 'A'. Can you explain this answer?
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