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The sum of 1 + 1/3 + 1/32 + 1/33 + … + 1/3 n –1 is
- a)2/3
- b)3/2
- c)4/5
- d)none of these
Correct answer is option 'D'. Can you explain this answer?
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The sum of 1 + 1/3 + 1/32 + 1/33 + … + 1/3 n –1 isa)2/3b)3...
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The sum of 1 + 1/3 + 1/32 + 1/33 + … + 1/3 n –1 isa)2/3b)3...
Given sum: 1 + 1/3 + 1/32 + 1/33 + ... + 1/3n + 1
To find the sum of this series, we need to use the formula for the sum of an infinite geometric series:
Sum = a / (1 - r)
where a is the first term and r is the common ratio.
Let's first find the common ratio:
r = (1/3) / (1/32) = 32/3
Now, let's find the first term:
a = 1
Using the formula, we get:
Sum = 1 / (1 - 32/3) = 1 / (-29/3) = -3/29
Therefore, the correct answer is option D, none of these.
To find the sum of this series, we need to use the formula for the sum of an infinite geometric series:
Sum = a / (1 - r)
where a is the first term and r is the common ratio.
Let's first find the common ratio:
r = (1/3) / (1/32) = 32/3
Now, let's find the first term:
a = 1
Using the formula, we get:
Sum = 1 / (1 - 32/3) = 1 / (-29/3) = -3/29
Therefore, the correct answer is option D, none of these.
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The sum of 1 + 1/3 + 1/32 + 1/33 + … + 1/3 n –1 isa)2/3b)3...
Its a trick question and use your tricky method 1+1/3+........ than answer must be less than 1.5 and greater than 1than no optiona are justifying the answer because our answer will be around 1.4 than option D is correct answer.
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The sum of 1 + 1/3 + 1/32 + 1/33 + … + 1/3 n –1 isa)2/3b)3/2c)4/5d)none of theseCorrect answer is option 'D'. Can you explain this answer?
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