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If in the equation ax2 + bx + c = 0, a, b and c are in an A.R and sum of the roots is 5 greater than product of the roots, find the modulus of harmonic mean of the roots.
    Correct answer is '5.5'. Can you explain this answer?
    Verified Answer
    If in the equation ax2 + bx + c = 0, a, b and c are in an A.R and sum ...
    Since, a, b and c are in an A.R
    2 b = c + a
    Also,
    Solving (i) and (ii) we get,
    —bla = 4/3 and da =-11/3
    Answer: 5.5
    This question is part of UPSC exam. View all CAT courses
    Most Upvoted Answer
    If in the equation ax2 + bx + c = 0, a, b and c are in an A.R and sum ...
    Given:
    The equation is ax^2 + bx + c = 0, where a, b, and c are in an arithmetic progression (A.P.).
    The sum of the roots is 5 greater than the product of the roots.

    To find:
    The modulus of the harmonic mean of the roots.

    Solution:

    Step 1: Find the roots of the quadratic equation:
    Let the roots of the quadratic equation be α and β.

    Sum of the roots (α + β) = -b/a
    Product of the roots (α * β) = c/a

    Given that the sum of the roots is 5 greater than the product of the roots:
    α + β = 5 + αβ

    Substituting the values of the sum and product of the roots:
    -b/a = 5 + c/a

    Simplifying the equation:
    b/a = -5 - c/a
    b = -5a - c

    Substituting the value of b in the quadratic equation:
    ax^2 + (-5a - c)x + c = 0

    Step 2: Determine the arithmetic progression:
    Given that a, b, and c are in an arithmetic progression (A.P.), we have:
    b - a = c - b

    Simplifying the equation:
    2b = a + c
    a = 2b - c

    Substituting the value of a in the quadratic equation:
    (2b - c)x^2 + (-5a - c)x + c = 0

    Step 3: Apply the harmonic mean formula:
    The harmonic mean of two numbers is given by:
    Harmonic Mean = 2/(1/α + 1/β)

    Let the roots α and β be in the form (b - m) and (b + m), where m is the common difference of the arithmetic progression.

    Substituting the values in the harmonic mean formula:
    Harmonic Mean = 2/(1/(b - m) + 1/(b + m))

    Simplifying the expression:
    Harmonic Mean = 2/((2b)/(b^2 - m^2))
    Harmonic Mean = (b^2 - m^2)/(2b)

    Step 4: Calculate the modulus of the harmonic mean:
    The modulus of the harmonic mean is given by the absolute value of the harmonic mean.

    Taking the absolute value of the expression:
    |Harmonic Mean| = |(b^2 - m^2)/(2b)|

    Since we need to find the modulus of the harmonic mean, it doesn't matter if the roots are positive or negative.

    Step 5: Substitute the value of a in terms of b and c:
    Substituting the value of a in terms of b and c:
    a = 2b - c

    Step 6: Simplify the expression:
    |Harmonic Mean| = |((2b - c)^2 - m^2)/(2b)|

    Step 7: Apply the condition that the sum of the roots is 5 greater than the product of the roots:
    α + β = 5 + αβ

    Substituting the values of α and β:
    (b - m) + (b + m) = 5 + (b -
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    If in the equation ax2 + bx + c = 0, a, b and c are in an A.R and sum of the roots is 5 greater than product of the roots, find the modulus of harmonic mean of the roots.Correct answer is '5.5'. Can you explain this answer?
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