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A body of mass 44 kg is moving at a velocity of 10 m/s is brought to rest in 10mins, the work done is:
- a)220 J
- b)22000 J
- c)22 J
- d)-2200J
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
A body of mass 44 kg is moving at a velocity of 10 m/s is brought to r...
Mass (m)- 44 kg
initial velocity (u) - 10m/s
final velocity (v) - 0
time (t)- 10min =600s
At first,
acceleration (a) = v-u/t
=0-10/600 = -1/60m per sec square
using 2nd equation of motion
s = ut +1/2at^2
s = 10*600 + 1/2*(-1/60*600*600)
s=3000m
Now, 2nd law of motion
Force = ma = 44*(-1/60)=-11/15 N
finally,
work done=F*s=-11/15*3000= -22000J
initial velocity (u) - 10m/s
final velocity (v) - 0
time (t)- 10min =600s
At first,
acceleration (a) = v-u/t
=0-10/600 = -1/60m per sec square
using 2nd equation of motion
s = ut +1/2at^2
s = 10*600 + 1/2*(-1/60*600*600)
s=3000m
Now, 2nd law of motion
Force = ma = 44*(-1/60)=-11/15 N
finally,
work done=F*s=-11/15*3000= -22000J
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Community Answer
A body of mass 44 kg is moving at a velocity of 10 m/s is brought to r...
Given:
Mass of the body (m) = 44 kg
Initial velocity (u) = 10 m/s
Final velocity (v) = 0 m/s (body is brought to rest)
Time taken (t) = 10 mins = 10 x 60 = 600 seconds
To find:
Work done (W)
Formula:
The work done on an object is given by the equation:
W = 0.5 * m * (v^2 - u^2)
Calculation:
Substituting the given values into the formula:
W = 0.5 * 44 * (0^2 - 10^2)
= 0.5 * 44 * (-100)
= - 2200 J
Answer:
The work done on the body is -2200 J.
Mass of the body (m) = 44 kg
Initial velocity (u) = 10 m/s
Final velocity (v) = 0 m/s (body is brought to rest)
Time taken (t) = 10 mins = 10 x 60 = 600 seconds
To find:
Work done (W)
Formula:
The work done on an object is given by the equation:
W = 0.5 * m * (v^2 - u^2)
Calculation:
Substituting the given values into the formula:
W = 0.5 * 44 * (0^2 - 10^2)
= 0.5 * 44 * (-100)
= - 2200 J
Answer:
The work done on the body is -2200 J.
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A body of mass 44 kg is moving at a velocity of 10 m/s is brought to rest in 10mins, the work done is:a)220 Jb)22000 Jc)22 Jd)-2200JCorrect answer is option 'D'. Can you explain this answer?
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