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The radius of the circle given by 2x2 + 2y2 – x = 0 is
- a)1/4
- b)1
- c)2
- d)1/2
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
The radius of the circle given by 2x2+ 2y2– x = 0 isa)1/4b)1c)2d...
2x² + 2y² - x = 0 .
==> 2 ( x² + y² - x/2 ) = 0 .
==> 2/2 ( x² + y² - x/2 ) = 0/2 .
==> x² - x/2 + y² = 0 .
==> ( x² - x/2 + (1/4)² ) + y² = (1/4)² .
==> ( x - 1/4 )² + ( y - 0 )² = (1/4)²
Centre (-¼, 0) radius(¼)
==> 2 ( x² + y² - x/2 ) = 0 .
==> 2/2 ( x² + y² - x/2 ) = 0/2 .
==> x² - x/2 + y² = 0 .
==> ( x² - x/2 + (1/4)² ) + y² = (1/4)² .
==> ( x - 1/4 )² + ( y - 0 )² = (1/4)²
Centre (-¼, 0) radius(¼)
Most Upvoted Answer
The radius of the circle given by 2x2+ 2y2– x = 0 isa)1/4b)1c)2d...
Hiiiiiiii, Pooja the equation of circle is X2+ y2 = r2, where r is radius. divide the given equation by 2, then X2+ Y2 -x/2=0, make it complete square, by adding and subtraction of the square of half the cofficient of x.
then equation is....
X2+Y2 -X/2+1/16-1/16=0then it become(X-1/4)2 -Y2= 1/16then it comes in general form so r2=1/16, r=1/4.
is this useful.....
then equation is....
X2+Y2 -X/2+1/16-1/16=0then it become(X-1/4)2 -Y2= 1/16then it comes in general form so r2=1/16, r=1/4.
is this useful.....
Community Answer
The radius of the circle given by 2x2+ 2y2– x = 0 isa)1/4b)1c)2d...
Just compare the equation with standard eq of circle after convention the given eq into the standard form( as in std. eq of circle the coefficients of x² and y² are 1 so divide the given eq by 2) and find out the center of the circle and then find out radius by the formula r=underroot( g²+f²-c)
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The radius of the circle given by 2x2+ 2y2– x = 0 isa)1/4b)1c)2d)1/2Correct answer is option 'A'. Can you explain this answer?
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The radius of the circle given by 2x2+ 2y2– x = 0 isa)1/4b)1c)2d)1/2Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The radius of the circle given by 2x2+ 2y2– x = 0 isa)1/4b)1c)2d)1/2Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The radius of the circle given by 2x2+ 2y2– x = 0 isa)1/4b)1c)2d)1/2Correct answer is option 'A'. Can you explain this answer?.
The radius of the circle given by 2x2+ 2y2– x = 0 isa)1/4b)1c)2d)1/2Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The radius of the circle given by 2x2+ 2y2– x = 0 isa)1/4b)1c)2d)1/2Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The radius of the circle given by 2x2+ 2y2– x = 0 isa)1/4b)1c)2d)1/2Correct answer is option 'A'. Can you explain this answer?.
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