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If B is a non–singular matrix and A is a square matrix, then det (B–1 AB) is equal to
  • a)
    det (A–1)
  • b)
    det (B–1)
  • c)
    Det (A)
  • d)
    Det (B)
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
If B is a non–singular matrix and A is a squarematrix, then det ...
A is a square matrix and B is non-singular matrix, so B is invertible and a square matrix.
 
det(B−1 AB)
 
=det(B−1 BA)
 
=det(InA)  (where In is an identity matrix of order n )
 
=det(A)
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If B is a non–singular matrix and A is a squarematrix, then det (B–1AB) is equal toa)det (A–1)b)det (B–1)c)Det (A)d)Det (B)Correct answer is option 'C'. Can you explain this answer?
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