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A particle moves in the xy plane under the action of a force F such that the value of its linear momentum (P) at any time t is, Px = 2 cost, Py = 2 sint. The angle q between P and F at that time t will be -
  • a)
    0º 
  • b)
    30º
  • c)
    90º 
  • d)
    180º
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A particle moves in the xy plane under the action of a forceFsuch that...
Fx = dpx / dt = - 2sint
Fy = dpy / dt = 2cost
So angle between F and will be 90º  because we see that their dot product is zero.
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Most Upvoted Answer
A particle moves in the xy plane under the action of a forceFsuch that...
Fx = dpx / dt = - 2sint
Fy = dpy / dt = 2cost
So angle between F and will be 90º  because we see that their dot product is zero.
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A particle moves in the xy plane under the action of a forceFsuch that...
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A particle moves in the xy plane under the action of a forceFsuch that the value of its linear momentum (P) at any time t is, Px= 2 cost, Py= 2 sint. The angle q betweenPandFat that time t will be -a)0ºb)30ºc)90ºd)180ºCorrect answer is option 'C'. Can you explain this answer?
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