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 A coin is tossed. If head comes up a die is thrown but if tail comes up, the coin is tossed again. The probability of obtaining head and number 6 is:
  • a)
    1/8
  • b)
    5/8
  • c)
    7/8
  • d)
    3/8
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A coin is tossed. If head comes up a die is thrown but if tail comes u...
Sample space = {(H, 1), (H, 2), (H, 3), (H, 4), (H, 5), (H, 6), (T, H), (T, T)}
n(Sample space) = 8 
P(obtaining head and number 6) = P(H, 6) = 1/8
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Most Upvoted Answer
A coin is tossed. If head comes up a die is thrown but if tail comes u...
Probability of obtaining head and number 6:

- Coin Toss:
The first step in solving this problem is to determine the probability of obtaining a head on the first coin toss. Since the coin has two possible outcomes (head or tail) and each outcome is equally likely, the probability of obtaining a head is 1/2.

- Die Roll:
Next, we need to determine the probability of rolling a number 6 on a die. A standard die has six sides, numbered 1 to 6, and each side is equally likely to come up. Therefore, the probability of rolling a number 6 is 1/6.

- Conditional Probability:
Now that we have the individual probabilities, we need to calculate the conditional probability of obtaining a head and a number 6. In this case, the die is only rolled if a head comes up on the coin toss. So, the probability of obtaining a head and a number 6 is equal to the probability of obtaining a head multiplied by the probability of rolling a number 6 given that a head has come up.

P(head and 6) = P(head) * P(6 | head)

P(head and 6) = (1/2) * (1/6)

P(head and 6) = 1/12

- Coin Toss Again:
However, we also need to consider the possibility of obtaining a tail on the first coin toss. If a tail comes up, the coin is tossed again. In this case, we go through the same process of calculating the conditional probability.

P(tail) = 1/2

P(head on second toss) = 1/2

P(head and 6 | tail) = P(head on second toss) * P(6 | head on second toss)

P(head and 6 | tail) = (1/2) * (1/6)

P(head and 6 | tail) = 1/12

- Total Probability:
To find the total probability of obtaining a head and a number 6, we need to consider both possibilities: obtaining a head on the first toss or obtaining a tail on the first toss and then a head on the second toss.

P(head and 6) = P(head and 6 | head) * P(head) + P(head and 6 | tail) * P(tail)

P(head and 6) = (1/12) * (1/2) + (1/12) * (1/2)

P(head and 6) = 1/24 + 1/24

P(head and 6) = 2/24

P(head and 6) = 1/12

Therefore, the probability of obtaining a head and a number 6 is 1/12, which is equivalent to option 'A' (1/8) in the given answer choices.
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A coin is tossed. If head comes up a die is thrown but if tail comes up, the coin is tossed again. The probability of obtaining head and number 6 is:a)1/8b)5/8c)7/8d)3/8Correct answer is option 'A'. Can you explain this answer?
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A coin is tossed. If head comes up a die is thrown but if tail comes up, the coin is tossed again. The probability of obtaining head and number 6 is:a)1/8b)5/8c)7/8d)3/8Correct answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A coin is tossed. If head comes up a die is thrown but if tail comes up, the coin is tossed again. The probability of obtaining head and number 6 is:a)1/8b)5/8c)7/8d)3/8Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A coin is tossed. If head comes up a die is thrown but if tail comes up, the coin is tossed again. The probability of obtaining head and number 6 is:a)1/8b)5/8c)7/8d)3/8Correct answer is option 'A'. Can you explain this answer?.
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