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Acetic acid, CH3COOH can form a dimer (CH3COOH)2 in the gas phase. The dimer is held together by two H-bonds with a total strength of 66.5 kJ per mol of dimer. If at 25°C, the equilibrium constant for the dimerization is 1.3 × 103 then ΔS° for the reaction is (– x Joule) then x (upto 2 decimal place):Correct answer is between '162.50,163.50'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about Acetic acid, CH3COOH can form a dimer (CH3COOH)2 in the gas phase. The dimer is held together by two H-bonds with a total strength of 66.5 kJ per mol of dimer. If at 25°C, the equilibrium constant for the dimerization is 1.3 × 103 then ΔS° for the reaction is (– x Joule) then x (upto 2 decimal place):Correct answer is between '162.50,163.50'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Acetic acid, CH3COOH can form a dimer (CH3COOH)2 in the gas phase. The dimer is held together by two H-bonds with a total strength of 66.5 kJ per mol of dimer. If at 25°C, the equilibrium constant for the dimerization is 1.3 × 103 then ΔS° for the reaction is (– x Joule) then x (upto 2 decimal place):Correct answer is between '162.50,163.50'. Can you explain this answer?.

Solutions for Acetic acid, CH3COOH can form a dimer (CH3COOH)2 in the gas phase. The dimer is held together by two H-bonds with a total strength of 66.5 kJ per mol of dimer. If at 25°C, the equilibrium constant for the dimerization is 1.3 × 103 then ΔS° for the reaction is (– x Joule) then x (upto 2 decimal place):Correct answer is between '162.50,163.50'. Can you explain this answer? in English & in Hindi are available as part of our courses for IIT JAM. Download more important topics, notes, lectures and mock test series for IIT JAM Exam by signing up for free.

Here you can find the meaning of Acetic acid, CH3COOH can form a dimer (CH3COOH)2 in the gas phase. The dimer is held together by two H-bonds with a total strength of 66.5 kJ per mol of dimer. If at 25°C, the equilibrium constant for the dimerization is 1.3 × 103 then ΔS° for the reaction is (– x Joule) then x (upto 2 decimal place):Correct answer is between '162.50,163.50'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Acetic acid, CH3COOH can form a dimer (CH3COOH)2 in the gas phase. The dimer is held together by two H-bonds with a total strength of 66.5 kJ per mol of dimer. If at 25°C, the equilibrium constant for the dimerization is 1.3 × 103 then ΔS° for the reaction is (– x Joule) then x (upto 2 decimal place):Correct answer is between '162.50,163.50'. Can you explain this answer?, a detailed solution for Acetic acid, CH3COOH can form a dimer (CH3COOH)2 in the gas phase. The dimer is held together by two H-bonds with a total strength of 66.5 kJ per mol of dimer. If at 25°C, the equilibrium constant for the dimerization is 1.3 × 103 then ΔS° for the reaction is (– x Joule) then x (upto 2 decimal place):Correct answer is between '162.50,163.50'. Can you explain this answer? has been provided alongside types of Acetic acid, CH3COOH can form a dimer (CH3COOH)2 in the gas phase. The dimer is held together by two H-bonds with a total strength of 66.5 kJ per mol of dimer. If at 25°C, the equilibrium constant for the dimerization is 1.3 × 103 then ΔS° for the reaction is (– x Joule) then x (upto 2 decimal place):Correct answer is between '162.50,163.50'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Acetic acid, CH3COOH can form a dimer (CH3COOH)2 in the gas phase. The dimer is held together by two H-bonds with a total strength of 66.5 kJ per mol of dimer. If at 25°C, the equilibrium constant for the dimerization is 1.3 × 103 then ΔS° for the reaction is (– x Joule) then x (upto 2 decimal place):Correct answer is between '162.50,163.50'. Can you explain this answer? tests, examples and also practice IIT JAM tests.