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Class 12 Exam  >  Class 12 Questions  >  For [Cu(NH3)4]2+, the correct statement isa)s... Start Learning for Free
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For [Cu(NH3)4]2+, the correct statement is
  • a)
    sp3 hybridisation, tetrahedral shape, one unpaired electron
  • b)
    dsp2 hybridisation, square planar shape, one
    unpaired electron in p-orbital
  • c)
    sp2d hybridisation, square planar shape, one
    unpaired electron in d-orbital
  • d)
    dsp3 hybridisation, tetrahedral molecule, one lone pair of electrons
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
For [Cu(NH3)4]2+, the correct statement isa)sp3 hybridisation, tetrahe...
Explanation:
The complex [Cu(NH3)4]2+ contains a Cu2+ ion coordinated with four NH3 ligands. The hybridization and shape of the complex can be determined as follows:

Hybridization:
The Cu2+ ion has a d9 electron configuration, with one unpaired electron in the d-orbitals. To form the complex, the Cu2+ ion will undergo hybridization to form four hybrid orbitals that will be used to bond with the NH3 ligands. The hybridization can be determined using the formula:

Hybridization = Number of valence electrons on central atom + Number of monodentate ligands – Charge on the complex

Hybridization = 9 + 4 – 2 = 11
Therefore, the hybridization of the Cu2+ ion in [Cu(NH3)4]2+ is dsp2.

Shape:
The dsp2 hybridization results in a square planar shape for the complex. The four NH3 ligands are arranged around the Cu2+ ion in a plane, with bond angles of 90°. The structure of the complex is shown below:

[NH3]→Cu←[NH3]
↑ ↓
[NH3]←Cu→[NH3]

Unpaired electron:
The dsp2 hybridization leads to one unpaired electron in one of the d-orbitals of the Cu2+ ion. This unpaired electron can participate in chemical reactions, making the complex reactive.

Therefore, the correct option is (B) dsp2 hybridization, square planar shape, one unpaired electron in p-orbital.
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Community Answer
For [Cu(NH3)4]2+, the correct statement isa)sp3 hybridisation, tetrahe...
Hyb is dsp2 because excited of n-1electron to np electron hence its UE lies in 4p
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For [Cu(NH3)4]2+, the correct statement isa)sp3 hybridisation, tetrahedral shape, one unpaired electronb)dsp2 hybridisation, square planar shape, oneunpaired electron in p-orbitalc)sp2d hybridisation, square planar shape, oneunpaired electron in d-orbitald)dsp3 hybridisation, tetrahedral molecule, one lone pair of electronsCorrect answer is option 'B'. Can you explain this answer?
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For [Cu(NH3)4]2+, the correct statement isa)sp3 hybridisation, tetrahedral shape, one unpaired electronb)dsp2 hybridisation, square planar shape, oneunpaired electron in p-orbitalc)sp2d hybridisation, square planar shape, oneunpaired electron in d-orbitald)dsp3 hybridisation, tetrahedral molecule, one lone pair of electronsCorrect answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about For [Cu(NH3)4]2+, the correct statement isa)sp3 hybridisation, tetrahedral shape, one unpaired electronb)dsp2 hybridisation, square planar shape, oneunpaired electron in p-orbitalc)sp2d hybridisation, square planar shape, oneunpaired electron in d-orbitald)dsp3 hybridisation, tetrahedral molecule, one lone pair of electronsCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For [Cu(NH3)4]2+, the correct statement isa)sp3 hybridisation, tetrahedral shape, one unpaired electronb)dsp2 hybridisation, square planar shape, oneunpaired electron in p-orbitalc)sp2d hybridisation, square planar shape, oneunpaired electron in d-orbitald)dsp3 hybridisation, tetrahedral molecule, one lone pair of electronsCorrect answer is option 'B'. Can you explain this answer?.
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