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The Inverse h–1 when h(x) = log10x is
- a)log10x
- b)10x
- c)log10(1/x)
- d)none of these
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
The Inverse h–1 when h(x) = log10x isa)log10xb)10xc)log10(1/x)d)...
Inverse of h(x) = log10x
To find the inverse of a function, we need to switch the roles of x and y and solve for y.
Let y = h(x) = log10x
Switching x and y, we get x = log10y
Rewrite in exponential form, we get:
10^x = y
Therefore, the inverse of h(x) is:
h^-1(x) = 10^x
Option B, 10x, matches the inverse of h(x), so it is the correct answer.
To find the inverse of a function, we need to switch the roles of x and y and solve for y.
Let y = h(x) = log10x
Switching x and y, we get x = log10y
Rewrite in exponential form, we get:
10^x = y
Therefore, the inverse of h(x) is:
h^-1(x) = 10^x
Option B, 10x, matches the inverse of h(x), so it is the correct answer.
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Community Answer
The Inverse h–1 when h(x) = log10x isa)log10xb)10xc)log10(1/x)d)...
h(x) =logX=y
X=e^y
h^-1(y)=e^y
h^-1(x)=e^x
e=10
Therefore h^-1(x)=10^x
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