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Aqueous solutions of two compounds M1—O—H and M2—O—H are prepared in two different breakers. If the electronegativity of M1 = 3.4, M2 = 1.2, O = 3.5, and H = 2.1, then the nature of two solutions will be respectively:
  • a)
    Acidic, Basic
  • b)
    Acidic, Acidic
  • c)
    Basic, Acidic
  • d)
    Basic, Basic
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Aqueous solutions of two compounds M1—O—H and M2—O&#...
Explanation:
Electronegativity is the measure of the tendency of an atom to attract a bonding pair of electrons. The higher the electronegativity of an atom, the more it attracts electrons towards itself.

The electronegativity of M1 and M2 are 3.4 and 1.2 respectively. Since M1 has a higher electronegativity, it will have a stronger attraction towards the O-H bond and will be able to pull the electron density towards itself. This will result in the release of H+ ions and make the solution acidic.

On the other hand, M2 has a lower electronegativity and will have a weaker attraction towards the O-H bond. As a result, it will not be able to release H+ ions and the solution will remain basic.

Therefore, the solution of M1OH will be acidic and the solution of M2OH will be basic.

Summary:
- M1OH solution will be acidic
- M2OH solution will be basic
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Community Answer
Aqueous solutions of two compounds M1—O—H and M2—O&#...
For M1-O-H the difference of electronegativity of M1-O bond is 0.1 and for O-H bond it is 1.4. As the difference of electronegativity in O-H bond is more than that of M1-O bond so O-H bond will break ,means it's aqous solution will be acidic. For M2-OH the difference of en of M2- O bond is 2.3 and for O-H it is 1.4, M2-O will break. and OH- will be liberated and it's solution will be basic.
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