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Find the overall order of a reaction whose rate constant is k = 3 x 10 -4 s-1
- a)Third
- b)Second
- c)Zero
- d)First
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
Find the overall order of a reaction whose rate constant is k = 3 x 10...
The overall order of a reaction is the sum of the individual orders of the reactants in the rate law. The rate law expresses the relationship between the rate of a chemical reaction and the concentrations of the reactants.
Given that the rate constant (k) is 3 x 10^-4 s^-1, we can determine the order of the reaction by analyzing the units of k.
We know that the overall order of a reaction is determined by adding the individual orders of the reactants. The order of a reactant is the exponent to which its concentration is raised in the rate law.
The units of k for a given reaction can be determined by analyzing the units of the rate law. In this case, we have:
k = rate / [reactant]^n
where n is the order of the reactant in the rate law.
The units of k are s^-1, which means that the units of rate must be in mol/L/s and the units of [reactant] must be in mol/L in order for the units to cancel out and leave only s^-1.
Since we are given only the value of k, we cannot directly determine the individual orders of the reactants. However, we can infer the overall order of the reaction based on the units of k.
Since k has units of s^-1, the units of rate must be mol/L/s. This means that the overall order of the reaction must be 1 (first order).
Therefore, the correct answer is option D: First.
Given that the rate constant (k) is 3 x 10^-4 s^-1, we can determine the order of the reaction by analyzing the units of k.
We know that the overall order of a reaction is determined by adding the individual orders of the reactants. The order of a reactant is the exponent to which its concentration is raised in the rate law.
The units of k for a given reaction can be determined by analyzing the units of the rate law. In this case, we have:
k = rate / [reactant]^n
where n is the order of the reactant in the rate law.
The units of k are s^-1, which means that the units of rate must be in mol/L/s and the units of [reactant] must be in mol/L in order for the units to cancel out and leave only s^-1.
Since we are given only the value of k, we cannot directly determine the individual orders of the reactants. However, we can infer the overall order of the reaction based on the units of k.
Since k has units of s^-1, the units of rate must be mol/L/s. This means that the overall order of the reaction must be 1 (first order).
Therefore, the correct answer is option D: First.
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Find the overall order of a reaction whose rate constant is k = 3 x 10...
Units:- for K can be calculated by (Mole)^1-n (Litre )n-1 Time ^-1...Here,n is order of the reaction ....On substituting n=1.We get, K units as;K=(Mole)1-1( Litre)1-1 sec-1.K=sec-1.......So, option D is correct....
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Find the overall order of a reaction whose rate constant is k = 3 x 10 -4 s-1a)Thirdb)Secondc)Zerod)FirstCorrect answer is option 'D'. Can you explain this answer?
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Find the overall order of a reaction whose rate constant is k = 3 x 10 -4 s-1a)Thirdb)Secondc)Zerod)FirstCorrect answer is option 'D'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Find the overall order of a reaction whose rate constant is k = 3 x 10 -4 s-1a)Thirdb)Secondc)Zerod)FirstCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find the overall order of a reaction whose rate constant is k = 3 x 10 -4 s-1a)Thirdb)Secondc)Zerod)FirstCorrect answer is option 'D'. Can you explain this answer?.
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