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A vessel contains 0.5 mole each of SO2, H2 and CH4.  Its outlet was made open and closed after some time. Thus, order of partial pressure inside the vessel will be
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A vessel contains 0.5 mole each of SO2, H2 and CH4. Its outlet was mad...
From Graham's law of diffusion, the rate of diffusion of a gas through a slit or any outlet or inlet in a container, is inversely proportional to the molecular weight of the gas.
So , for a definite time (say t), SO2 will diffuse in the least amount through the outlet as it has highest mass among the three. Similarly the next in the increasing order will be CH4 and finally the last one is H2 will diffuse in the most amount.
Thus, the final amount of gases in the container are in the order SO2 > CH4 > H2.
It's clear that more the amount of the gas, more is its partial pressure.
So, the correct order is P(SO2) > P(CH4) > P(H2)
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Most Upvoted Answer
A vessel contains 0.5 mole each of SO2, H2 and CH4. Its outlet was mad...
KEY POINT :

From Graham's law of diffusion, the rate of diffusion of a gas through a slit or any outlet or inlet in a container, is inversely proportional to the molecular weight of the gas.

So , for a definite time (say t), SO2 will diffuse in the least amount through the outlet as it has highest mass among the three. Similarly the next in the increasing order will be CH4 and finally the last one is H2 will diffuse in the most amount.

Thus, the final amount of gases in the container are in the order SO2 > CH4 > H2.

It's clear that more the amount of the gas, more is its partial pressure.

So, the correct order is P(SO2) > P(CH4) > P(H2)
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Community Answer
A vessel contains 0.5 mole each of SO2, H2 and CH4. Its outlet was mad...
From Graham's law of diffusion, the rate of diffusion of a gas through a slit or any outlet or inlet in a container, is inversely proportional to the molecular weight of the gas.
So , for a definite time (say t), SO2 will diffuse in the least amount through the outlet as it has highest mass among the three. Similarly the next in the increasing order will be CH4 and finally the last one is H2 will diffuse in the most amount.
Thus, the final amount of gases in the container are in the order SO2 > CH4 > H2.
It's clear that more the amount of the gas, more is its partial pressure.
So, the correct order is P(SO2) > P(CH4) > P(H2)
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A vessel contains 0.5 mole each of SO2, H2 and CH4. Its outlet was made open and closed after some time. Thus, order of partial pressure inside the vessel will bea)b)c)d)Correct answer is option 'A'. Can you explain this answer?
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