What is the 10th A.M between 2 and 57 if 10 A.M s are inserted between...
2 and 57 have 10 terms between them so including them there would be 12 terms
an = 57, a = 2, n = 12
an = a + (n-1)d
=> 57 = 2 + (12 - 1)d
=> 55 = 11d
d = 5
T10 = a + 10d
=> 2 + 10(5)
= 52
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What is the 10th A.M between 2 and 57 if 10 A.M s are inserted between...
The problem states that we need to find the 10th A.M. (Arithmetic Mean) between 2 and 57, given that 10 A.M.s are inserted between these numbers. To solve this problem, we can use the formula for the nth A.M.:
An = a + (n - 1)d
Where An represents the nth A.M., a is the first term in the sequence, n is the position of the A.M., and d is the common difference.
Let's apply this formula to find the first A.M. between 2 and 57. In this case, a = 2 and d = (57 - 2) / 10 = 5.5. Plugging these values into the formula, we get:
A1 = 2 + (1 - 1) * 5.5 = 2
So, the first A.M. is 2.
To find the 10th A.M., we simply need to plug in n = 10 into the formula. Using a = 2 and d = 5.5, we have:
A10 = 2 + (10 - 1) * 5.5 = 2 + 9 * 5.5 = 2 + 49.5 = 51.5
Therefore, the 10th A.M. between 2 and 57 is 51.5. However, none of the given options match 51.5. So, let's check the closest option.
The closest option to 51.5 is option 'C', which is 52. While it is not the exact answer, it is the closest option to the 10th A.M. between 2 and 57.
What is the 10th A.M between 2 and 57 if 10 A.M s are inserted between...
All the 12 numbers starting with 2, the 10 AM's in between and ending with 57 will be in APSo,57 = 2 + (12 - 1)d55 = 11dd = 5The 10th AM will be the 11th term in the seriesT = 2 + (11 - 1)(5)T = 52
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