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If y=c is a tangent to the circle x2+y2–2x+2y–2 =0 at (1, 1), then the value of c isa)1b)2c)–1d)–2Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about If y=c is a tangent to the circle x2+y2–2x+2y–2 =0 at (1, 1), then the value of c isa)1b)2c)–1d)–2Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If y=c is a tangent to the circle x2+y2–2x+2y–2 =0 at (1, 1), then the value of c isa)1b)2c)–1d)–2Correct answer is option 'A'. Can you explain this answer?.

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