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Two dice are thrown simultaneously. The probability of getting an even number as the sum is:

  • a)
    1/2

  • b)
    3/4

  • c)
    1/4

  • d)
    1/3

Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Two dice are thrown simultaneously. The probability of getting an even...
each dice can show 1,3 or 5..so ways of getting OD
D product= 3∗3=93∗3=9Total ways to ch
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Most Upvoted Answer
Two dice are thrown simultaneously. The probability of getting an even...
Possible outcomes :
{1,1};{1,2};{1,3};{1,4};{1,5};{1,6}
{2,1};{2,2};{2,3};{2,4};{2,5};{2,6}
{3,1};{3,2};{3,3};{3,4};{3,5};{3,6}
{4,1};{4,2};{4,3};{4,4};{4,5};{4,6}
{5,1};{5,2};{5,3};{5,4};{5,5};{5,6}
{6,1};{6,2};{6,3};{6,4};{6,5};{6,6}
Total outcomes = 36
Favorable events : an even number as the sum :{1,1};{1,3};{1,5};{2,2};{2,4};{2,6};{3,1};{3,3};{3,5};{4,2};{4,4};{4,6};{5,1};{5,3}{5,5};{6,2};{6,4};{6,6} =18
 
So, the probability of getting an even number as the sum:
= Favorable events/Total events
= 18/36
 = 1/2
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Two dice are thrown simultaneously. The probability of getting an even number as the sum is:a)1/2b)3/4c)1/4d)1/3Correct answer is option 'A'. Can you explain this answer?
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