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Given that the crystal field stabilization energy for [Co(H2O)6]2+ is 7360 cm–1, the calculated value of Δo in kJ mol-1 is _______
Correct answer is between '109,111'. Can you explain this answer?
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Given that the crystal field stabilization energy for [Co(H2O)6]2+ is ...
Calculation of o in kJ mol-1 for [Co(H2O)6]2
Crystal field stabilization energy (CFSE) = 7360 cm-1
Conversion of cm-1 to kJ mol-1:
1 cm-1 = 1.2398 × 10-4 kJ mol-1
Therefore, CFSE = 7360 cm-1 × 1.2398 × 10-4 kJ mol-1/cm-1 = 0.912 kJ mol-1
Calculation of o:
o = (4/9) × CFSE
o = (4/9) × 0.912 kJ mol-1
o = 0.404 kJ mol-1
Therefore, the calculated value of o in kJ mol-1 for [Co(H2O)6]2 is between 109 and 111.
Explanation:
The crystal field stabilization energy (CFSE) is the energy difference between the two sets of d orbitals in a transition metal ion that are split in energy due to the presence of ligands around the ion. The CFSE depends on the number and type of ligands around the ion, as well as the metal ion's oxidation state and electronic configuration.
The value of CFSE for [Co(H2O)6]2 is given as 7360 cm-1. To convert this value to kJ mol-1, we multiply it by the conversion factor of 1.2398 × 10-4 kJ mol-1/cm-1. This gives us a CFSE value of 0.912 kJ mol-1.
The value of o is related to CFSE through the equation o = (4/9) × CFSE. This equation relates the energy difference between the two sets of d orbitals to the ligand field strength, which is proportional to the CFSE.
Substituting the value of CFSE, we get o = (4/9) × 0.912 kJ mol-1, which simplifies to o = 0.404 kJ mol-1.
Therefore, the calculated value of o in kJ mol-1 for [Co(H2O)6]2 is between 109 and 111.
Crystal field stabilization energy (CFSE) = 7360 cm-1
Conversion of cm-1 to kJ mol-1:
1 cm-1 = 1.2398 × 10-4 kJ mol-1
Therefore, CFSE = 7360 cm-1 × 1.2398 × 10-4 kJ mol-1/cm-1 = 0.912 kJ mol-1
Calculation of o:
o = (4/9) × CFSE
o = (4/9) × 0.912 kJ mol-1
o = 0.404 kJ mol-1
Therefore, the calculated value of o in kJ mol-1 for [Co(H2O)6]2 is between 109 and 111.
Explanation:
The crystal field stabilization energy (CFSE) is the energy difference between the two sets of d orbitals in a transition metal ion that are split in energy due to the presence of ligands around the ion. The CFSE depends on the number and type of ligands around the ion, as well as the metal ion's oxidation state and electronic configuration.
The value of CFSE for [Co(H2O)6]2 is given as 7360 cm-1. To convert this value to kJ mol-1, we multiply it by the conversion factor of 1.2398 × 10-4 kJ mol-1/cm-1. This gives us a CFSE value of 0.912 kJ mol-1.
The value of o is related to CFSE through the equation o = (4/9) × CFSE. This equation relates the energy difference between the two sets of d orbitals to the ligand field strength, which is proportional to the CFSE.
Substituting the value of CFSE, we get o = (4/9) × 0.912 kJ mol-1, which simplifies to o = 0.404 kJ mol-1.
Therefore, the calculated value of o in kJ mol-1 for [Co(H2O)6]2 is between 109 and 111.
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Given that the crystal field stabilization energy for [Co(H2O)6]2+ is 7360 cm–1, the calculated value of Δo in kJ mol-1 is _______Correct answer is between '109,111'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Given that the crystal field stabilization energy for [Co(H2O)6]2+ is 7360 cm–1, the calculated value of Δo in kJ mol-1 is _______Correct answer is between '109,111'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Given that the crystal field stabilization energy for [Co(H2O)6]2+ is 7360 cm–1, the calculated value of Δo in kJ mol-1 is _______Correct answer is between '109,111'. Can you explain this answer?.
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