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The age of a person is twice the sum of the ages of his two sons and five years ago his age was thrice the sum of their ages. Find his present ages. 
  • a)
    60 years 
  • b)
    52 years 
  • c)
    51 years 
  • d)
    50 years. 
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
The age of a person is twice the sum of the ages of his two sons and f...
Given:
- Age of a person = 2*(age of son1 + age of son2)
- 5 years ago, person's age = 3*(age of son1 5 years ago + age of son2 5 years ago)

To find: Present age of person

Solution:
Let the age of son1 be x and age of son2 be y.
Using the given information, we can write two equations:

- 2(x+y) = P (where P represents present age of person)
- 3(x-5 + y-5) = P-5 (age of person 5 years ago is P-5, age of sons 5 years ago is x-5 and y-5)

Simplifying these equations, we get:

- 2x + 2y = P
- 3x + 3y - 30 = P - 5
- 3x + 3y = P + 25

Substituting equation 1 in equation 3, we get:

- 3x + 3y = 2x + 2y + 25
- x + y = 25

Substituting x + y = 25 in equation 1, we get:

- 2(25) = P
- P = 50

Therefore, the present age of person is 50 years.
Free Test
Community Answer
The age of a person is twice the sum of the ages of his two sons and f...
Answer will be D .
as father = 2 (sum of 2 sons)
5 years ago
father = 3 (sum of 2 sons)
so 50 is divisible by 2
and 50-5 = 45 is divisible by 3
therefore ans will be D
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The age of a person is twice the sum of the ages of his two sons and five years ago his age was thrice the sum of their ages. Find his present ages.a)60 yearsb)52 yearsc)51 yearsd)50 years.Correct answer is option 'D'. Can you explain this answer?
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