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0.202 g of a carbon compound, on combustion, gave 0.361 g of carbon dioxide and 0.47 g of water. Calculate
the percentage composition of carbon :-
  • a)
    48.76%
  • b)
    8.07%
  • c)
    43.17%
  • d)
    42.17%
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
0.202 g of a carbon compound, on combustion, gave 0.361 g of carbon di...
Given,

Mass of carbon compound = 0.202 g

Mass of carbon dioxide = 0.361 g

Mass of water = 0.47 g

Molar mass of carbon = 12 g/mole

Molar mass of Carbon dioxide = 44 g/mole

First we have to calculate the moles of .

Moles of  = 

The moles of  = 0.008205 moles

In , there are 1 carbon atom and 2 atom molecules are present.

So, the moles of  is equal to the moles of .

The moles of  = 0.008205 moles

Now we have to calculate the mass of Carbon.

Mass of Carbon = Moles of Carbon X Molar mass of Carbon

Mass of Carbon = 0.008205 moles X 12 g/mole = 0.09846 g

Now we have to calculate the % composition of Carbon.


Therefore, the % composition of Carbon is 48.743%.
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Most Upvoted Answer
0.202 g of a carbon compound, on combustion, gave 0.361 g of carbon di...
Given:
Mass of carbon compound = 0.202 g
Mass of CO2 produced = 0.361 g
Mass of H2O produced = 0.47 g

To calculate the percentage composition of carbon in the given compound, we need to find out the mass of carbon present in it.

1. Calculation of mass of carbon:

Mass of carbon in CO2 = mass of CO2 x (mass of carbon/molecular mass of CO2)
= 0.361 x 12/44
= 0.098 g

Mass of carbon in H2O = mass of H2O x (mass of carbon/molecular mass of H2O)
= 0.47 x 12/18
= 0.392 g

Total mass of carbon in the compound = 0.098 + 0.392
= 0.49 g

2. Calculation of percentage composition of carbon:

Percentage composition of carbon = (mass of carbon/total mass of compound) x 100
= (0.49/0.202) x 100
= 243.07%

Therefore, the correct answer is option A) 48.76%. The answer can also be rounded off to 49%.
Free Test
Community Answer
0.202 g of a carbon compound, on combustion, gave 0.361 g of carbon di...
Given,

Mass of carbon compound = 0.202 g

Mass of carbon dioxide = 0.361 g

Mass of water = 0.47 g

Molar mass of carbon = 12 g/mole

Molar mass of Carbon dioxide = 44 g/mole

First we have to calculate the moles of .

Moles of CO2 = 0.361/44

The moles of Co2 = 0.008205 moles

In , there are 1 carbon atom and 2 atom molecules are present.

So, the moles of is equal to the moles of .

The moles of = 0.008205 moles

Now we have to calculate the mass of Carbon.

Mass of Carbon = Moles of Carbon X Molar mass of Carbon

Mass of Carbon = 0.008205 moles X 12 g/mole = 0.09846 g

Now we have to calculate the % composition of Carbon.

(0.0984/0.202 ) × 100 = 48.76%

Therefore, the % composition of Carbon is 48.743%.
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0.202 g of a carbon compound, on combustion, gave 0.361 g of carbon dioxide and 0.47 g of water. Calculatethe percentage composition of carbon :-a)48.76%b)8.07%c)43.17%d)42.17%Correct answer is option 'A'. Can you explain this answer?
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0.202 g of a carbon compound, on combustion, gave 0.361 g of carbon dioxide and 0.47 g of water. Calculatethe percentage composition of carbon :-a)48.76%b)8.07%c)43.17%d)42.17%Correct answer is option 'A'. Can you explain this answer? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about 0.202 g of a carbon compound, on combustion, gave 0.361 g of carbon dioxide and 0.47 g of water. Calculatethe percentage composition of carbon :-a)48.76%b)8.07%c)43.17%d)42.17%Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 0.202 g of a carbon compound, on combustion, gave 0.361 g of carbon dioxide and 0.47 g of water. Calculatethe percentage composition of carbon :-a)48.76%b)8.07%c)43.17%d)42.17%Correct answer is option 'A'. Can you explain this answer?.
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