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Calculate the number of gram atoms present in 8g of helium
  • a)
    3
  • b)
    4
  • c)
    2
  • d)
    1
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Calculate the number of gram atoms present in 8g of heliuma)3b)4c)2d)1...
Atomic mass of Helium is 4. So if you take 4 grams of Helium atom,then the number of atoms in it will be 6.0203x10^23,that is avogadro number. If you take 8 grams of Helium,then it will be double of avogadro number. Ans: 2x6.023x10^23

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Community Answer
Calculate the number of gram atoms present in 8g of heliuma)3b)4c)2d)1...
To calculate the number of gram atoms present in 8g of helium, we need to use the concept of molar mass and Avogadro's number.

1. Molar Mass of Helium:
The molar mass of helium (He) is 4 g/mol. This means that one mole of helium atoms has a mass of 4 grams.

2. Avogadro's Number:
Avogadro's number is the number of atoms or molecules present in one mole of a substance. It is approximately equal to 6.022 x 10^23.

3. Calculation:
To find the number of gram atoms present in 8g of helium, we can use the following steps:

Step 1: Calculate the moles of helium.
Moles = Mass / Molar Mass
Moles = 8g / 4 g/mol
Moles = 2 mol

Step 2: Calculate the number of atoms.
Number of Atoms = Moles x Avogadro's Number
Number of Atoms = 2 mol x 6.022 x 10^23
Number of Atoms = 1.2044 x 10^24 atoms

Step 3: Convert the number of atoms to gram atoms.
Gram Atoms = Number of Atoms / Avogadro's Number
Gram Atoms = 1.2044 x 10^24 atoms / 6.022 x 10^23
Gram Atoms = 2

Therefore, the number of gram atoms present in 8g of helium is 2.
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