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0.126g of an acid requires 20ml of 0.1NAOH for complete neutralization.Eq.wt.of the acid is: a)45. b)53. c)40. d)63 correct ans is 63.can anyone explain how?
Verified Answer
0.126g of an acid requires 20ml of 0.1NAOH for complete neutralization...
Normality=no. Of eq/volume
0.1=(no. Of eq/20)x1000
(0.1x20)/1000=no. Of eq
0.002=given mass/eq mass
Eq mass =0.126/0.002=63
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Most Upvoted Answer
0.126g of an acid requires 20ml of 0.1NAOH for complete neutralization...
Eq.wt. of the acid = ?
Given:
Volume of NaOH solution (V) = 20 mL
Normality of NaOH solution (N) = 0.1 N
Mass of acid required for complete neutralization = 0.126 g
To find the equivalent weight (Eq.wt.) of the acid, we can use the formula:
Eq.wt. = (Mass of acid required) / (Volume of NaOH solution × Normality of NaOH solution)
Let's calculate:
1. Calculating the Eq.wt. of the acid:
Eq.wt. = (0.126 g) / (20 mL × 0.1 N)
2. Conversion of volume from mL to L:
Volume of NaOH solution (V) = 20 mL = 20/1000 L = 0.02 L
3. Substituting the values:
Eq.wt. = (0.126 g) / (0.02 L × 0.1 N)
Eq.wt. = (0.126 g) / (0.002 N L)
Eq.wt. = 63 g/N L
Therefore, the equivalent weight (Eq.wt.) of the acid is 63 g.
Answer: d) 63
Given:
Volume of NaOH solution (V) = 20 mL
Normality of NaOH solution (N) = 0.1 N
Mass of acid required for complete neutralization = 0.126 g
To find the equivalent weight (Eq.wt.) of the acid, we can use the formula:
Eq.wt. = (Mass of acid required) / (Volume of NaOH solution × Normality of NaOH solution)
Let's calculate:
1. Calculating the Eq.wt. of the acid:
Eq.wt. = (0.126 g) / (20 mL × 0.1 N)
2. Conversion of volume from mL to L:
Volume of NaOH solution (V) = 20 mL = 20/1000 L = 0.02 L
3. Substituting the values:
Eq.wt. = (0.126 g) / (0.02 L × 0.1 N)
Eq.wt. = (0.126 g) / (0.002 N L)
Eq.wt. = 63 g/N L
Therefore, the equivalent weight (Eq.wt.) of the acid is 63 g.
Answer: d) 63
Community Answer
0.126g of an acid requires 20ml of 0.1NAOH for complete neutralization...
Thanks....can u ans one more question of mine?
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0.126g of an acid requires 20ml of 0.1NAOH for complete neutralization.Eq.wt.of the acid is: a)45. b)53. c)40. d)63 correct ans is 63.can anyone explain how?
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0.126g of an acid requires 20ml of 0.1NAOH for complete neutralization.Eq.wt.of the acid is: a)45. b)53. c)40. d)63 correct ans is 63.can anyone explain how? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about 0.126g of an acid requires 20ml of 0.1NAOH for complete neutralization.Eq.wt.of the acid is: a)45. b)53. c)40. d)63 correct ans is 63.can anyone explain how? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 0.126g of an acid requires 20ml of 0.1NAOH for complete neutralization.Eq.wt.of the acid is: a)45. b)53. c)40. d)63 correct ans is 63.can anyone explain how?.
0.126g of an acid requires 20ml of 0.1NAOH for complete neutralization.Eq.wt.of the acid is: a)45. b)53. c)40. d)63 correct ans is 63.can anyone explain how? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about 0.126g of an acid requires 20ml of 0.1NAOH for complete neutralization.Eq.wt.of the acid is: a)45. b)53. c)40. d)63 correct ans is 63.can anyone explain how? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 0.126g of an acid requires 20ml of 0.1NAOH for complete neutralization.Eq.wt.of the acid is: a)45. b)53. c)40. d)63 correct ans is 63.can anyone explain how?.
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