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The sum of 3 numbers of a G P is 39 and their product is 729. The numbers are
  • a)
    3, 27, 9
  • b)
    9, 3, 27
  • c)
    3, 9, 27
  • d)
    none of these
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
The sum of 3 numbers of a G P is 39 and their product is 729. The numb...
Option (C) is correct

39 = ar + ar^2 + ar^3 
729 = (ar) * (ar^2) * (ar^3) 

729 = (ar) * (ar^2) * (ar^3) 
729 = (ar)^3 * r^3 
9^3 = (ar)^3 * r^3 
9 = ar * r 
9 = ar^2 

39 = ar + ar^2 + ar^3 
39 = ar^2 / r + ar^2 + ar^2 * r 
39 = 9/r + 9 + 9r 
13 = 3/r + 3 + 3r 
13r = 3 + 3r + 3r^2 
0 = 3 - 10r + 3r^2 

r = (10 +/- sqrt(100 - 36)) / 6 
r = (10 +/- 8) / 6 
r = 18/6 , 2/6 
r = 3 , 1/3 

ar^2 = 9 
a * 3^2 , a * (1/3)^2 = 9 
a * 9 , a * (1/9) = 9 
a = 1 , 81 

If r = 3, then: 

ar , ar^2 , ar^3 => 
1 * 3 , 1 * 3^2 , 1 * 3^3 => 
3 , 9 , 27 

If r = 1/3, then: 

ar , ar^2 + ar^3 => 
81 / 3 , 81 / 9 , 81 / 27 => 
27 , 9 , 3 

Either way, the 3 numbers are 3 , 9 , and 27.
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Community Answer
The sum of 3 numbers of a G P is 39 and their product is 729. The numb...
Given:
The sum of 3 numbers of a G P is 39 and their product is 729.

To find:
The three numbers in the G P.

Solution:
Let the three numbers be a, ar and ar^2.

According to the given condition,
a + ar + ar^2 = 39 ...(1)
a × ar × ar^2 = 729
a^3 r^3 = 729
ar = 9 ...(2)

Substituting (2) in (1),
a + 9 + 9r = 39
a + 9r = 30 ...(3)

Substituting (2) in (3),
a + (a/9)×9 = 30
a + a = 30
2a = 30
a = 15

Substituting a = 15 in (2),
ar = 9
r = 9/15 = 3/5

Therefore, the three numbers in the G P are:
a = 15, ar = 9 and ar^2 = 27/5

Hence, option (c) 3, 9, 27 is the correct answer.
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The sum of 3 numbers of a G P is 39 and their product is 729. The numbers area)3, 27, 9b)9, 3, 27c)3, 9, 27d)none of theseCorrect answer is option 'C'. Can you explain this answer?
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