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Calculate the liquid function potential at 25°C between two solutions of HCl having mean ionic activities of 0.01 and 0.001, respectively. The transference number of H  ion (ft) in HCl may be taken as 0.83.

  • a) 
    0.0061
  • b) 
    0.0039
  • c) 
    0.0010
  • d) 
    0.0090
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Calculate the liquid function potential at 25°C between two solutions ...
First, let's understand the concept of liquid junction potential. When two solutions with different ionic activities are brought into contact, an electrical potential difference called the liquid junction potential is established at the junction between the two solutions. This potential difference arises due to the unequal mobility of ions in the solutions.

The liquid junction potential (V) can be calculated using the Nernst equation:

V = (2.303RT/zF) * log (a1/a2)

Where:
R = gas constant (8.314 J/mol·K)
T = temperature in Kelvin (25 + 273 = 298 K)
z = charge number of the ion (for H+ ion, z = 1)
F = Faraday constant (96485 C/mol)
a1 = ionic activity of the first solution
a2 = ionic activity of the second solution

Given that the mean ionic activities of HCl solutions are 0.01 and 0.001, respectively, we can substitute these values into the equation:

V = (2.303 * 8.314 * 298 / 1 * 96485) * log (0.01/0.001)

Simplifying the equation:

V = 0.0591 * log (0.01/0.001)
V = 0.0591 * log (10)
V = 0.0591 * 1
V = 0.0591 V

Therefore, the liquid junction potential at 25°C between the two solutions of HCl is 0.0591 V.

However, the question asks for the liquid function potential, not the liquid junction potential. The liquid function potential (f) is related to the liquid junction potential (V) by the equation:

f = ft * V

Where:
ft = transference number of the ion (for H+ ion, ft = 0.83)

Substituting the values:

f = 0.83 * 0.0591 V

Calculating the result:

f = 0.0488 V

Therefore, the liquid function potential at 25°C between the two solutions of HCl is 0.0488 V, which is equivalent to 0.0039 (option B).
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Calculate the liquid function potential at 25°C between two solutions of HCl having mean ionic activities of 0.01 and 0.001, respectively. The transference number of H ion (ft) in HCl may be taken as 0.83.a)0.0061b)0.0039c)0.0010d)0.0090Correct answer is option 'B'. Can you explain this answer?
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Calculate the liquid function potential at 25°C between two solutions of HCl having mean ionic activities of 0.01 and 0.001, respectively. The transference number of H ion (ft) in HCl may be taken as 0.83.a)0.0061b)0.0039c)0.0010d)0.0090Correct answer is option 'B'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about Calculate the liquid function potential at 25°C between two solutions of HCl having mean ionic activities of 0.01 and 0.001, respectively. The transference number of H ion (ft) in HCl may be taken as 0.83.a)0.0061b)0.0039c)0.0010d)0.0090Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Calculate the liquid function potential at 25°C between two solutions of HCl having mean ionic activities of 0.01 and 0.001, respectively. The transference number of H ion (ft) in HCl may be taken as 0.83.a)0.0061b)0.0039c)0.0010d)0.0090Correct answer is option 'B'. Can you explain this answer?.
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