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Consider a uniform thin circular disk of radius R and mass M. A concentric square of side R/2 is cut out from the disk (see figure). What is the moment of inertia of the resultant disk about an axis passing through the centre of the disk and perpendicular to it ?
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Consider a uniform thin circular disk of radius R and mass M. A concen...
Moment of inertia of the circular disc about a line perpendicular to the circular disc through it's center=MR^2/2 .now if we cut out a square lamina of side R/2 then moment of inertia of this square lamina about a line perpendicular to the lamina and passing through the center=W/3((R^2/4)+(R^2/4)) where w=4.(R/4)(R/4).density of the squre lamina now the required moment of inertia = M(R^2)/2)_(R^4/48.2).density. ( by putting the value of w). again M=πR^2.density now putting the value of density we get the results=(MR^/2)(1-(1/48π))
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Consider a uniform thin circular disk of radius R and mass M. A concentric square of side R/2 is cut out from the disk (see figure). What is the moment of inertia of the resultant disk about an axis passing through the centre of the disk and perpendicular to it ?a)b)c)d)Correct answer is option 'B'. Can you explain this answer?
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