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The value of charge on the oil droplets experimentally observed were -1.6×10 power-19 and-4×10power -19 coulomb. The value of the electronic charge indicated by these results is ? And: -0.8×10 power -19 but how?
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The value of charge on the oil droplets experimentally observed were -...
Calculating the Electronic Charge
To calculate the electronic charge, we need to use the formula:
q = ne
Where q is the charge on the oil droplet, n is the number of electrons on the droplet, and e is the electronic charge.
Calculating the Electronic Charge for the First Droplet
For the first droplet, the charge observed was -1.6×10^-19 C. We can assume that this droplet carries a negative charge. Therefore, we can write:
q = ne
-1.6×10^-19 = n x (-1.6×10^-19)
Solving for n, we get:
n = 1
This means that the droplet carries one electron. Substituting this value of n in the formula gives us:
e = q/n
e = (-1.6×10^-19)/1
e = -1.6×10^-19 C
Therefore, the electronic charge indicated by this result is -1.6×10^-19 C.
Calculating the Electronic Charge for the Second Droplet
For the second droplet, the charge observed was -4×10^-19 C. We can assume that this droplet also carries a negative charge. Therefore, we can write:
q = ne
-4×10^-19 = n x (-1.6×10^-19)
Solving for n, we get:
n = 2.5
This means that the droplet carries 2.5 electrons. Substituting this value of n in the formula gives us:
e = q/n
e = (-4×10^-19)/2.5
e = -1.6×10^-19 C
Therefore, the electronic charge indicated by this result is also -1.6×10^-19 C.
Explanation for the Second Result
The second result (-0.8×10^-19 C) mentioned in the question is incorrect. This might be due to a calculation error or a typo. The correct value is -1.6×10^-19 C, which is the same as the first result. This is because the electronic charge is a fundamental constant and does not change. The charge on the droplet is determined by the number of electrons on it, which can be fractional in some cases. However, the electronic charge remains the same.
To calculate the electronic charge, we need to use the formula:
q = ne
Where q is the charge on the oil droplet, n is the number of electrons on the droplet, and e is the electronic charge.
Calculating the Electronic Charge for the First Droplet
For the first droplet, the charge observed was -1.6×10^-19 C. We can assume that this droplet carries a negative charge. Therefore, we can write:
q = ne
-1.6×10^-19 = n x (-1.6×10^-19)
Solving for n, we get:
n = 1
This means that the droplet carries one electron. Substituting this value of n in the formula gives us:
e = q/n
e = (-1.6×10^-19)/1
e = -1.6×10^-19 C
Therefore, the electronic charge indicated by this result is -1.6×10^-19 C.
Calculating the Electronic Charge for the Second Droplet
For the second droplet, the charge observed was -4×10^-19 C. We can assume that this droplet also carries a negative charge. Therefore, we can write:
q = ne
-4×10^-19 = n x (-1.6×10^-19)
Solving for n, we get:
n = 2.5
This means that the droplet carries 2.5 electrons. Substituting this value of n in the formula gives us:
e = q/n
e = (-4×10^-19)/2.5
e = -1.6×10^-19 C
Therefore, the electronic charge indicated by this result is also -1.6×10^-19 C.
Explanation for the Second Result
The second result (-0.8×10^-19 C) mentioned in the question is incorrect. This might be due to a calculation error or a typo. The correct value is -1.6×10^-19 C, which is the same as the first result. This is because the electronic charge is a fundamental constant and does not change. The charge on the droplet is determined by the number of electrons on it, which can be fractional in some cases. However, the electronic charge remains the same.
Community Answer
The value of charge on the oil droplets experimentally observed were -...
Charge on the oil drop (q) . charge on the electron (e) q=ne, where n is number of electrons. e=q/n=−1.6×10−19/n=−4×10−19/n′.n/n'=-1.6×10^-19/-4×10^-19.n/n'=0.4.n/n'=4/10.n/n'=2/5.For n and n' to have integer values, n=2.and n′=5.Hence, e=q/n.=−1.6×10−19/2=−4×10−19/5.=-0.8×10^-19.....
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The value of charge on the oil droplets experimentally observed were -1.6×10 power-19 and-4×10power -19 coulomb. The value of the electronic charge indicated by these results is ? And: -0.8×10 power -19 but how?
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The value of charge on the oil droplets experimentally observed were -1.6×10 power-19 and-4×10power -19 coulomb. The value of the electronic charge indicated by these results is ? And: -0.8×10 power -19 but how? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The value of charge on the oil droplets experimentally observed were -1.6×10 power-19 and-4×10power -19 coulomb. The value of the electronic charge indicated by these results is ? And: -0.8×10 power -19 but how? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The value of charge on the oil droplets experimentally observed were -1.6×10 power-19 and-4×10power -19 coulomb. The value of the electronic charge indicated by these results is ? And: -0.8×10 power -19 but how?.
The value of charge on the oil droplets experimentally observed were -1.6×10 power-19 and-4×10power -19 coulomb. The value of the electronic charge indicated by these results is ? And: -0.8×10 power -19 but how? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The value of charge on the oil droplets experimentally observed were -1.6×10 power-19 and-4×10power -19 coulomb. The value of the electronic charge indicated by these results is ? And: -0.8×10 power -19 but how? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The value of charge on the oil droplets experimentally observed were -1.6×10 power-19 and-4×10power -19 coulomb. The value of the electronic charge indicated by these results is ? And: -0.8×10 power -19 but how?.
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