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For a standard normal distribution, the points of inflexion are given by
- a)µ – σ and µ + σ.
- b)– σ and σ.
- c)–1 and 1.
- d)0 and 1.
Correct answer is option 'C'. Can you explain this answer?
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For a standard normal distribution, the points of inflexion are given ...
Explanation:
A standard normal distribution refers to a normal distribution with a mean of 0 and a standard deviation of 1. The points of inflexion on a normal distribution curve occur where the curve changes from being concave upwards to concave downwards, or vice versa. These points are located at one standard deviation away from the mean on either side of the curve.
Therefore, the correct answer is option 'C', where the points of inflexion are located at 1 standard deviation away from the mean on either side of the curve, which is represented by the values of x = 1 and x = -1.
To summarize:
- A standard normal distribution has a mean of 0 and a standard deviation of 1.
- Points of inflexion on a normal distribution curve occur where the curve changes from being concave upwards to concave downwards, or vice versa.
- The points of inflexion on a standard normal distribution curve are located at 1 standard deviation away from the mean on either side of the curve, which is represented by the values of x = 1 and x = -1.
A standard normal distribution refers to a normal distribution with a mean of 0 and a standard deviation of 1. The points of inflexion on a normal distribution curve occur where the curve changes from being concave upwards to concave downwards, or vice versa. These points are located at one standard deviation away from the mean on either side of the curve.
Therefore, the correct answer is option 'C', where the points of inflexion are located at 1 standard deviation away from the mean on either side of the curve, which is represented by the values of x = 1 and x = -1.
To summarize:
- A standard normal distribution has a mean of 0 and a standard deviation of 1.
- Points of inflexion on a normal distribution curve occur where the curve changes from being concave upwards to concave downwards, or vice versa.
- The points of inflexion on a standard normal distribution curve are located at 1 standard deviation away from the mean on either side of the curve, which is represented by the values of x = 1 and x = -1.
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For a standard normal distribution, the points of inflexion are given ...
For standard Normal distribution mean=0 and sigma =1 So putting these values we get the final answer as -1 and 1
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For a standard normal distribution, the points of inflexion are given bya)µ – σ and µ + σ.b)– σ and σ.c)–1 and 1.d)0 and 1.Correct answer is option 'C'. Can you explain this answer?
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