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Ramu completes 30% of work in 7.5 days. Raju is 50% as efficient as Ramu, Venu is 50% as efficient as Raju. Now Raju and Venu joined with Ramu for the rest of the work then in how many days will take to complete the work?
- a)9 Days
- b)10 Days
- c)12 Days
- d)15 Days
- e)None of these
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Ramu completes 30% of work in 7.5 days. Raju is 50% as efficient as Ra...
Ramu takes 25 days to complete work.
Raju = 50 days Venu = 100 days
Now 70% work is left
They can complete whole work in = 1/ 1/25+1/50+1/100
100/7 days then 70% in 10 days
Most Upvoted Answer
Ramu completes 30% of work in 7.5 days. Raju is 50% as efficient as Ra...
Given Information:
- Ramu completed 30% of work in 7.5 days.
- Raju is 50% as efficient as Ramu.
- Venu is 50% as efficient as Raju.
To find: Time taken by all three to complete the remaining work.
Approach:
Let's assume that the total work is equal to 100 units.
- Ramu completed 30% of the work in 7.5 days, which means he completed 30 units of work in 7.5 days.
- Therefore, Ramu's efficiency is 30/7.5 = 4 units per day.
Now, Raju is 50% as efficient as Ramu, which means his efficiency is 2 units per day.
Similarly, Venu is 50% as efficient as Raju, which means his efficiency is 1 unit per day.
Let's assume that all three work together for x days to complete the remaining 70 units of work.
Calculation:
- Ramu's work in x days = 4x
- Raju's work in x days = 2x
- Venu's work in x days = x
Total work done by all three in x days = 4x + 2x + x = 7x
According to the question,
Total work done by all three = Remaining work = 70 units
Therefore,
- 7x = 70
- x = 10 days
Hence, all three will take 10 days to complete the remaining work.
Answer: The correct option is (b) 10 days.
- Ramu completed 30% of work in 7.5 days.
- Raju is 50% as efficient as Ramu.
- Venu is 50% as efficient as Raju.
To find: Time taken by all three to complete the remaining work.
Approach:
Let's assume that the total work is equal to 100 units.
- Ramu completed 30% of the work in 7.5 days, which means he completed 30 units of work in 7.5 days.
- Therefore, Ramu's efficiency is 30/7.5 = 4 units per day.
Now, Raju is 50% as efficient as Ramu, which means his efficiency is 2 units per day.
Similarly, Venu is 50% as efficient as Raju, which means his efficiency is 1 unit per day.
Let's assume that all three work together for x days to complete the remaining 70 units of work.
Calculation:
- Ramu's work in x days = 4x
- Raju's work in x days = 2x
- Venu's work in x days = x
Total work done by all three in x days = 4x + 2x + x = 7x
According to the question,
Total work done by all three = Remaining work = 70 units
Therefore,
- 7x = 70
- x = 10 days
Hence, all three will take 10 days to complete the remaining work.
Answer: The correct option is (b) 10 days.
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Ramu completes 30% of work in 7.5 days. Raju is 50% as efficient as Ramu, Venu is 50% as efficient as Raju. Now Raju and Venu joined with Ramu for the rest of the work then in how many days will take to complete the work?a)9 Daysb)10 Daysc)12 Daysd)15 Dayse)None of theseCorrect answer is option 'B'. Can you explain this answer?
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