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Hybridization state of boron and oxygen in boric acid is:
- a)sp3, sp2
- b)sp2, sp3
- c)sp2, sp2
- d)sp3, sp3
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Hybridization state of boron and oxygen in boric acid is:a)sp3, sp2b)s...
The answer is b.
The central boron atom is binded to three hydroxyl groups. As boron has three electrons in the outermost shell and has to form three sigma bonds, it is sp2 hybridised. This means all the three bonds are in the same plane. Each oxygen atom is sp3 hybridised.
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Hybridization state of boron and oxygen in boric acid is:a)sp3, sp2b)s...
Hybridization of Boron in Boric Acid
Boric acid (H3BO3) contains boron as its central atom. The hybridization state of boron can be determined by analyzing its bonding and geometry.
- Valence Electrons: Boron has three valence electrons.
- Bonding: In boric acid, boron forms three sigma bonds with three hydroxyl (–OH) groups.
- Geometry: The arrangement of these bonds around boron leads to a trigonal planar geometry.
- Hybridization: To accommodate three sigma bonds and maintain trigonal planar geometry, boron undergoes sp2 hybridization.
Hybridization of Oxygen in Boric Acid
Oxygen in boric acid is part of the hydroxyl groups.
- Valence Electrons: Oxygen has six valence electrons.
- Bonding: Each oxygen atom forms one sigma bond with boron and one sigma bond with a hydrogen atom. Additionally, oxygen has two lone pairs of electrons.
- Geometry: The arrangement around each oxygen atom is tetrahedral due to the presence of two lone pairs and the bonding pairs.
- Hybridization: Given the four regions of electron density (two bonds and two lone pairs), the hybridization state of oxygen is sp3.
Conclusion
Thus, in boric acid:
- Boron: sp2 hybridization
- Oxygen: sp3 hybridization
This leads to the correct answer being option 'b'.
Boric acid (H3BO3) contains boron as its central atom. The hybridization state of boron can be determined by analyzing its bonding and geometry.
- Valence Electrons: Boron has three valence electrons.
- Bonding: In boric acid, boron forms three sigma bonds with three hydroxyl (–OH) groups.
- Geometry: The arrangement of these bonds around boron leads to a trigonal planar geometry.
- Hybridization: To accommodate three sigma bonds and maintain trigonal planar geometry, boron undergoes sp2 hybridization.
Hybridization of Oxygen in Boric Acid
Oxygen in boric acid is part of the hydroxyl groups.
- Valence Electrons: Oxygen has six valence electrons.
- Bonding: Each oxygen atom forms one sigma bond with boron and one sigma bond with a hydrogen atom. Additionally, oxygen has two lone pairs of electrons.
- Geometry: The arrangement around each oxygen atom is tetrahedral due to the presence of two lone pairs and the bonding pairs.
- Hybridization: Given the four regions of electron density (two bonds and two lone pairs), the hybridization state of oxygen is sp3.
Conclusion
Thus, in boric acid:
- Boron: sp2 hybridization
- Oxygen: sp3 hybridization
This leads to the correct answer being option 'b'.
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