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The final products in the reaction of BF3 with water are
- a)B(OH)3 and OF2
- b)H3BO3 and HBF4
- c)B2O3 and HBF4
- d)B2H6 and HF
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
The final products in the reaction of BF3 with water area)B(OH)3 and O...
Answer :
- b)H3BO3and HBF4
Boron trifluoride reacts with water to give
boric acid and fluoroboric acid.
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The final products in the reaction of BF3 with water area)B(OH)3 and O...
Reaction of BF3 with water
When BF3 is reacted with water, it undergoes hydrolysis to form different products depending on the amount of water added.
BF3 + H2O → H3O+ + BF3OH- (addition of one water molecule)
BF3 + 2H2O → H3O+ + [BF2(OH)2]- (addition of two water molecules)
BF3 + 3H2O → [H3O+][BF(OH)3]- (addition of three water molecules)
Final products
The final products of the reaction of BF3 with water are:
a) B(OH)3 and OF2
b) H3BO3 and HBF4
c) B2O3 and HBF4
d) B2H6 and HF
Out of these options, the correct answer is option 'B', which means that the final products are H3BO3 (boric acid) and HBF4 (tetrafluoroboric acid).
Explanation
When BF3 reacts with water, it undergoes hydrolysis to form boric acid (H3BO3) and tetrafluoroboric acid (HBF4). The reaction can be explained as follows:
BF3 + 3H2O → H3BO3 + HBF4
The first step of the reaction involves the addition of water molecules to BF3 to form H3O+ and [BF(OH)3]-. This intermediate product then undergoes further hydrolysis to form boric acid and tetrafluoroboric acid.
H3O+ + [BF(OH)3]- → H3BO3 + HBF4
Therefore, the correct answer is option 'B', which represents the final products of the reaction of BF3 with water as H3BO3 and HBF4.
When BF3 is reacted with water, it undergoes hydrolysis to form different products depending on the amount of water added.
BF3 + H2O → H3O+ + BF3OH- (addition of one water molecule)
BF3 + 2H2O → H3O+ + [BF2(OH)2]- (addition of two water molecules)
BF3 + 3H2O → [H3O+][BF(OH)3]- (addition of three water molecules)
Final products
The final products of the reaction of BF3 with water are:
a) B(OH)3 and OF2
b) H3BO3 and HBF4
c) B2O3 and HBF4
d) B2H6 and HF
Out of these options, the correct answer is option 'B', which means that the final products are H3BO3 (boric acid) and HBF4 (tetrafluoroboric acid).
Explanation
When BF3 reacts with water, it undergoes hydrolysis to form boric acid (H3BO3) and tetrafluoroboric acid (HBF4). The reaction can be explained as follows:
BF3 + 3H2O → H3BO3 + HBF4
The first step of the reaction involves the addition of water molecules to BF3 to form H3O+ and [BF(OH)3]-. This intermediate product then undergoes further hydrolysis to form boric acid and tetrafluoroboric acid.
H3O+ + [BF(OH)3]- → H3BO3 + HBF4
Therefore, the correct answer is option 'B', which represents the final products of the reaction of BF3 with water as H3BO3 and HBF4.
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