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The reaction of BCl3 with NH4Cl gives product A which upon reduction by NaBH4 gives product B. Product B upon reacting with HCl affords compound C which is:
  • a)
    Cl3B3N3H9
  • b)
    [ClBNH]3
  • c)
    [HBNH]3
  • d)
    (ClH)3B3N3(ClH)3
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The reaction of BCl3 with NH4Cl gives product A which upon reduction b...
Reaction and Products:
- BCl3 reacts with NH4Cl to give product A
- Product A is then reduced by NaBH4 to give product B
- Product B reacts with HCl to give compound C

Identification of Compound C:
- Compound C has the formula Cl3B3N3H9
- Therefore, the correct answer is option 'A'

Explanation:
The reaction between BCl3 and NH4Cl results in the formation of a Lewis adduct, product A. This is because BCl3 is an electron-deficient molecule and is able to accept a pair of electrons from the nitrogen atom in NH4Cl. The resulting product A is a boron-nitrogen-halide compound.

When product A is reduced by NaBH4, the boron atom in the molecule is reduced and product B is formed. Product B is a boron-nitrogen-hydride compound.

Finally, product B reacts with HCl to give compound C. The reaction between product B and HCl results in the displacement of a hydride ion by a chloride ion. Compound C is a boron-nitrogen-halide compound with the formula Cl3B3N3H9.

Therefore, the correct answer is option 'A'.
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Community Answer
The reaction of BCl3 with NH4Cl gives product A which upon reduction b...
Correct answer is (a) .

BCl3 + NH4Cl —> B3N3H3Cl3 + NaBH4 —> B3N3H6 + HCl —> Cl3B3N3H3

So the final product is Cl3B3N3H3
Correct answer is (a) .
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The reaction of BCl3 with NH4Cl gives product A which upon reduction by NaBH4 gives product B. Product B upon reacting with HCl affords compound C which is:a)Cl3B3N3H9b)[ClBNH]3c)[HBNH]3d)(ClH)3B3N3(ClH)3Correct answer is option 'A'. Can you explain this answer?
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