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A 26cm ladder is placed against a wall in such a way that the foot of the ladder is 10cm away from the wall is the upper end of the ladder
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A 26cm ladder is placed against a wall in such a way that the foot of ...
I think the distance between wall and inclined ladder is 10m. not 10 cm.
and I have drawn fig. according to it.
from fig.
it is a right angled triangle
wall length from the ground to the inclined ladder spot
using Pythagoras thoerem
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A 26cm ladder is placed against a wall in such a way that the foot of ...
Problem Statement:
A 26cm ladder is placed against a wall in such a way that the foot of the ladder is 10cm away from the wall. Determine the distance of the upper end of the ladder from the ground.
Solution:
To solve this problem, we can use the Pythagorean theorem, which states that in a right-angled triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the other two sides.
Given:
- Length of the ladder (hypotenuse) = 26 cm
- Distance of the foot of the ladder from the wall = 10 cm
We need to find the distance of the upper end of the ladder from the ground.
Step 1: Identify the right-angled triangle
In this problem, the ladder forms the hypotenuse of a right-angled triangle. Let's label the sides of the triangle.
- Hypotenuse (ladder) = 26 cm
- Base (distance of the foot of the ladder from the wall) = 10 cm
- Height (distance of the upper end of the ladder from the ground) = ?
Step 2: Apply the Pythagorean theorem
According to the Pythagorean theorem, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
So, we have:
(Height)^2 + (Base)^2 = (Hypotenuse)^2
(Height)^2 + (10 cm)^2 = (26 cm)^2
(Height)^2 + 100 cm^2 = 676 cm^2
(Height)^2 = 676 cm^2 - 100 cm^2
(Height)^2 = 576 cm^2
Step 3: Find the height
To find the height, we take the square root of both sides of the equation.
Height = √576 cm^2
Height = 24 cm
Step 4: Answer
The distance of the upper end of the ladder from the ground is 24 cm.
A 26cm ladder is placed against a wall in such a way that the foot of the ladder is 10cm away from the wall. Determine the distance of the upper end of the ladder from the ground.
Solution:
To solve this problem, we can use the Pythagorean theorem, which states that in a right-angled triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the other two sides.
Given:
- Length of the ladder (hypotenuse) = 26 cm
- Distance of the foot of the ladder from the wall = 10 cm
We need to find the distance of the upper end of the ladder from the ground.
Step 1: Identify the right-angled triangle
In this problem, the ladder forms the hypotenuse of a right-angled triangle. Let's label the sides of the triangle.
- Hypotenuse (ladder) = 26 cm
- Base (distance of the foot of the ladder from the wall) = 10 cm
- Height (distance of the upper end of the ladder from the ground) = ?
Step 2: Apply the Pythagorean theorem
According to the Pythagorean theorem, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
So, we have:
(Height)^2 + (Base)^2 = (Hypotenuse)^2
(Height)^2 + (10 cm)^2 = (26 cm)^2
(Height)^2 + 100 cm^2 = 676 cm^2
(Height)^2 = 676 cm^2 - 100 cm^2
(Height)^2 = 576 cm^2
Step 3: Find the height
To find the height, we take the square root of both sides of the equation.
Height = √576 cm^2
Height = 24 cm
Step 4: Answer
The distance of the upper end of the ladder from the ground is 24 cm.
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A 26cm ladder is placed against a wall in such a way that the foot of the ladder is 10cm away from the wall is the upper end of the ladder Related: NCERT Solution Chapter 6 (Part - 2) - Triangle and Its Properties, Maths, Class 7
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A 26cm ladder is placed against a wall in such a way that the foot of the ladder is 10cm away from the wall is the upper end of the ladder Related: NCERT Solution Chapter 6 (Part - 2) - Triangle and Its Properties, Maths, Class 7 for Class 7 2024 is part of Class 7 preparation. The Question and answers have been prepared according to the Class 7 exam syllabus. Information about A 26cm ladder is placed against a wall in such a way that the foot of the ladder is 10cm away from the wall is the upper end of the ladder Related: NCERT Solution Chapter 6 (Part - 2) - Triangle and Its Properties, Maths, Class 7 covers all topics & solutions for Class 7 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 26cm ladder is placed against a wall in such a way that the foot of the ladder is 10cm away from the wall is the upper end of the ladder Related: NCERT Solution Chapter 6 (Part - 2) - Triangle and Its Properties, Maths, Class 7.
A 26cm ladder is placed against a wall in such a way that the foot of the ladder is 10cm away from the wall is the upper end of the ladder Related: NCERT Solution Chapter 6 (Part - 2) - Triangle and Its Properties, Maths, Class 7 for Class 7 2024 is part of Class 7 preparation. The Question and answers have been prepared according to the Class 7 exam syllabus. Information about A 26cm ladder is placed against a wall in such a way that the foot of the ladder is 10cm away from the wall is the upper end of the ladder Related: NCERT Solution Chapter 6 (Part - 2) - Triangle and Its Properties, Maths, Class 7 covers all topics & solutions for Class 7 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 26cm ladder is placed against a wall in such a way that the foot of the ladder is 10cm away from the wall is the upper end of the ladder Related: NCERT Solution Chapter 6 (Part - 2) - Triangle and Its Properties, Maths, Class 7.
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