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A uniform body 3 m long, 2 m wide and 1 m deep floats in water. If the depth of immersion is 0.6 m, then the weight of the body is
- a)3.53 kN
- b)33.3 kN
- c)35.3 kN
- d)none of these
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
A uniform body 3 m long, 2 m wide and 1 m deep floats in water. If the...
Length 3 m; Width 2 m; Depth 1 m and depth of immersion 0.6 m.
We know that volume of water displaced
=3 x 2 x 0.6 =3.6 m3
and weight of the body = Weight of water displaced
= 9.81 x3.6 = 35.3 kN Ans.
Most Upvoted Answer
A uniform body 3 m long, 2 m wide and 1 m deep floats in water. If the...
Given:
Length of the body (l) = 3 m
Width of the body (b) = 2 m
Depth of the body (h) = 1 m
Depth of immersion (d) = 0.6 m
To find:
Weight of the body
Solution:
1. Volume of the body
The volume of the body can be calculated as:
V = l × b × h
V = 3 × 2 × 1
V = 6 m³
2. Volume of water displaced
The volume of water displaced by the body is equal to the volume of the body immersed in water. Since the depth of immersion is 0.6 m, the volume of water displaced is:
Vd = l × b × d
Vd = 3 × 2 × 0.6
Vd = 3.6 m³
3. Weight of water displaced
The weight of water displaced by the body is equal to the weight of the body. This is known as Archimedes' principle. The weight of water displaced can be calculated as:
Wd = Vd × ρ × g
where ρ is the density of water and g is the acceleration due to gravity.
Density of water (ρ) = 1000 kg/m³
Acceleration due to gravity (g) = 9.81 m/s²
Substituting the values, we get:
Wd = 3.6 × 1000 × 9.81
Wd = 35.316 N
4. Weight of the body
The weight of the body can be calculated as:
W = Wd
W = 35.316 N
Converting Newtons to kilonewtons, we get:
W = 0.0353 kN
Therefore, the weight of the body is 35.3 kN (approx). Hence, option (c) is the correct answer.
Length of the body (l) = 3 m
Width of the body (b) = 2 m
Depth of the body (h) = 1 m
Depth of immersion (d) = 0.6 m
To find:
Weight of the body
Solution:
1. Volume of the body
The volume of the body can be calculated as:
V = l × b × h
V = 3 × 2 × 1
V = 6 m³
2. Volume of water displaced
The volume of water displaced by the body is equal to the volume of the body immersed in water. Since the depth of immersion is 0.6 m, the volume of water displaced is:
Vd = l × b × d
Vd = 3 × 2 × 0.6
Vd = 3.6 m³
3. Weight of water displaced
The weight of water displaced by the body is equal to the weight of the body. This is known as Archimedes' principle. The weight of water displaced can be calculated as:
Wd = Vd × ρ × g
where ρ is the density of water and g is the acceleration due to gravity.
Density of water (ρ) = 1000 kg/m³
Acceleration due to gravity (g) = 9.81 m/s²
Substituting the values, we get:
Wd = 3.6 × 1000 × 9.81
Wd = 35.316 N
4. Weight of the body
The weight of the body can be calculated as:
W = Wd
W = 35.316 N
Converting Newtons to kilonewtons, we get:
W = 0.0353 kN
Therefore, the weight of the body is 35.3 kN (approx). Hence, option (c) is the correct answer.
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A uniform body 3 m long, 2 m wide and 1 m deep floats in water. If the...
At the top of a wide vertex weir 15.0 m long, the fluid head is 1.0 m towardsthe downstream. If the coefficient of discharge is 0.6, then the wear obtained fromThe maximum immersion will be:(a) 12.75 cumecs(c) 16.56 cumecs
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A uniform body 3 m long, 2 m wide and 1 m deep floats in water. If the depth of immersion is 0.6 m, then the weight of the body isa)3.53 kNb)33.3 kNc)35.3 kNd)none of theseCorrect answer is option 'C'. Can you explain this answer?
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A uniform body 3 m long, 2 m wide and 1 m deep floats in water. If the depth of immersion is 0.6 m, then the weight of the body isa)3.53 kNb)33.3 kNc)35.3 kNd)none of theseCorrect answer is option 'C'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A uniform body 3 m long, 2 m wide and 1 m deep floats in water. If the depth of immersion is 0.6 m, then the weight of the body isa)3.53 kNb)33.3 kNc)35.3 kNd)none of theseCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A uniform body 3 m long, 2 m wide and 1 m deep floats in water. If the depth of immersion is 0.6 m, then the weight of the body isa)3.53 kNb)33.3 kNc)35.3 kNd)none of theseCorrect answer is option 'C'. Can you explain this answer?.
A uniform body 3 m long, 2 m wide and 1 m deep floats in water. If the depth of immersion is 0.6 m, then the weight of the body isa)3.53 kNb)33.3 kNc)35.3 kNd)none of theseCorrect answer is option 'C'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A uniform body 3 m long, 2 m wide and 1 m deep floats in water. If the depth of immersion is 0.6 m, then the weight of the body isa)3.53 kNb)33.3 kNc)35.3 kNd)none of theseCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A uniform body 3 m long, 2 m wide and 1 m deep floats in water. If the depth of immersion is 0.6 m, then the weight of the body isa)3.53 kNb)33.3 kNc)35.3 kNd)none of theseCorrect answer is option 'C'. Can you explain this answer?.
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A uniform body 3 m long, 2 m wide and 1 m deep floats in water. If the depth of immersion is 0.6 m, then the weight of the body isa)3.53 kNb)33.3 kNc)35.3 kNd)none of theseCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for A uniform body 3 m long, 2 m wide and 1 m deep floats in water. If the depth of immersion is 0.6 m, then the weight of the body isa)3.53 kNb)33.3 kNc)35.3 kNd)none of theseCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of A uniform body 3 m long, 2 m wide and 1 m deep floats in water. If the depth of immersion is 0.6 m, then the weight of the body isa)3.53 kNb)33.3 kNc)35.3 kNd)none of theseCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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