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H2 gas was adsorbed on 1 g powdered copper surface forming monolayer of molecules. On desorption total H2 collected measured 1.36 cm3 at STP. Assuming volume of 1 molecule of H2 4.742 × 10–23 cm3, calculate specific area of copper powder
  • a)
    5.79 × 104
  • b)
    3.79 × 104
  • c)
    2.79 × 104
  • d)
    6.79 × 104
Correct answer is option 'A'. Can you explain this answer?
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Given data:
Mass of copper powder = 1 g
Volume of H2 collected at STP = 1.36 cm3
Volume of 1 molecule of H2 = 4.742 x 10^-23 cm3

To calculate:
Specific area of copper powder

Solution:
1. Using the ideal gas equation, we can calculate the number of moles of H2 adsorbed on copper powder.
PV = nRT
n = PV/RT
Here, P = 1 atm (STP), V = 1.36 cm3, R = 0.0821 L atm K^-1 mol^-1, and T = 273 K (STP)
n = (1.36 x 10^-3 L) (1 atm) / (0.0821 L atm K^-1 mol^-1) (273 K) = 6.08 x 10^-5 mol

2. Since a monolayer of H2 molecules is formed on the copper surface, the number of H2 molecules adsorbed is equal to the number of copper atoms on the surface. The surface area of copper powder can be calculated using the Avogadro's number (NA = 6.022 x 10^23 mol^-1) and the atomic mass of copper (63.55 g mol^-1).
Surface area of copper powder = (1 g / 63.55 g mol^-1) x NA = 9.46 x 10^20 cm2

3. The specific area of copper powder is the ratio of the surface area to the mass of powder.
Specific area of copper powder = surface area / mass of powder = 9.46 x 10^20 cm2 / 1 g
= 9.46 x 10^20 cm2 g^-1

4. To convert the specific area to the given units (cm^2 g^-1), we need to multiply by 10^-4.
Specific area of copper powder = 9.46 x 10^20 cm2 g^-1 x 10^-4 = 5.79 x 10^4 cm^2 g^-1

Therefore, the specific area of copper powder is 5.79 x 10^4 cm^2 g^-1, which is closest to option (A).
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H2 gas was adsorbed on 1 g powdered copper surface forming monolayer of molecules. On desorption total H2 collected measured 1.36 cm3 at STP. Assuming volume of 1 molecule of H2 4.742 × 10–23 cm3, calculate specific area of copper powdera)5.79 × 104b)3.79 × 104c)2.79 × 104d)6.79 × 104Correct answer is option 'A'. Can you explain this answer?
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H2 gas was adsorbed on 1 g powdered copper surface forming monolayer of molecules. On desorption total H2 collected measured 1.36 cm3 at STP. Assuming volume of 1 molecule of H2 4.742 × 10–23 cm3, calculate specific area of copper powdera)5.79 × 104b)3.79 × 104c)2.79 × 104d)6.79 × 104Correct answer is option 'A'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about H2 gas was adsorbed on 1 g powdered copper surface forming monolayer of molecules. On desorption total H2 collected measured 1.36 cm3 at STP. Assuming volume of 1 molecule of H2 4.742 × 10–23 cm3, calculate specific area of copper powdera)5.79 × 104b)3.79 × 104c)2.79 × 104d)6.79 × 104Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for H2 gas was adsorbed on 1 g powdered copper surface forming monolayer of molecules. On desorption total H2 collected measured 1.36 cm3 at STP. Assuming volume of 1 molecule of H2 4.742 × 10–23 cm3, calculate specific area of copper powdera)5.79 × 104b)3.79 × 104c)2.79 × 104d)6.79 × 104Correct answer is option 'A'. Can you explain this answer?.
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