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The rate of law for the reaction
RCl + NaOH → ROH + NaCl
is given by rate = k[RCl]. The rate of this reaction
  • a)
    Is doubled by doubling the concentration of NaOH
  • b)
    Is halved by reducing the concentration of RCl by one half
  • c)
    Is increased by increasing the temperature of the reaction
  • d)
    Is unaffected by change in temperature.
Correct answer is option 'B,C'. Can you explain this answer?
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The rate of law for the reactionRCl + NaOH → ROH + NaClis given b...
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The rate of law for the reactionRCl + NaOH → ROH + NaClis given by rate = k[RCl]. The rate of this reactiona)Is doubled by doubling the concentration of NaOHb)Is halved by reducing the concentration of RCl by one halfc)Is increased by increasing the temperature of the reactiond)Is unaffected by change in temperature.Correct answer is option 'B,C'. Can you explain this answer?
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The rate of law for the reactionRCl + NaOH → ROH + NaClis given by rate = k[RCl]. The rate of this reactiona)Is doubled by doubling the concentration of NaOHb)Is halved by reducing the concentration of RCl by one halfc)Is increased by increasing the temperature of the reactiond)Is unaffected by change in temperature.Correct answer is option 'B,C'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The rate of law for the reactionRCl + NaOH → ROH + NaClis given by rate = k[RCl]. The rate of this reactiona)Is doubled by doubling the concentration of NaOHb)Is halved by reducing the concentration of RCl by one halfc)Is increased by increasing the temperature of the reactiond)Is unaffected by change in temperature.Correct answer is option 'B,C'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The rate of law for the reactionRCl + NaOH → ROH + NaClis given by rate = k[RCl]. The rate of this reactiona)Is doubled by doubling the concentration of NaOHb)Is halved by reducing the concentration of RCl by one halfc)Is increased by increasing the temperature of the reactiond)Is unaffected by change in temperature.Correct answer is option 'B,C'. Can you explain this answer?.
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