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In a receiver the input signal is 100 V, while the internal noise at the input is 10 V. With amplification the output signal is 2 V, while the output noise is 0.4 V. The noise figure of receiver is
  • a)
    2
  • b)
    0.5
  • c)
    0.2
  • d)
    None of the mentioned
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
In a receiver the input signal is 100 V, while the internal noise at t...
NF = (100/10)/(2/0.4) or 2.
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Most Upvoted Answer
In a receiver the input signal is 100 V, while the internal noise at t...
Explanation:

The noise figure of a receiver is a measure of how much the noise from the receiver itself degrades the signal-to-noise ratio (SNR) of the input signal. It is defined as the ratio of the SNR at the input of the receiver to the SNR at the output of the receiver.

To calculate the noise figure, we need to determine the SNR at the input and output of the receiver.

Given:
Input signal voltage (Vin) = 100 V
Input noise voltage (Nin) = 10 V
Output signal voltage (Vout) = 2 V
Output noise voltage (Nout) = 0.4 V

Step 1: Calculate the input SNR:
SNRin = (Vin / Nin)^2

SNRin = (100 V / 10 V)^2
SNRin = 100^2
SNRin = 10000

Step 2: Calculate the output SNR:
SNRout = (Vout / Nout)^2

SNRout = (2 V / 0.4 V)^2
SNRout = 5^2
SNRout = 25

Step 3: Calculate the noise figure:
Noise figure (NF) = SNRin / SNRout

NF = 10000 / 25
NF = 400

The noise figure of the receiver is 400. However, the noise figure is often expressed in dB, which is given by:

Noise figure (NF) (dB) = 10 * log10(NF)

NF(dB) = 10 * log10(400)
NF(dB) = 10 * 2
NF(dB) = 20 dB

The noise figure of the receiver is 20 dB.

Conclusion:
The correct answer is option A) 2.
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In a receiver the input signal is 100 V, while the internal noise at the input is 10 V. With amplification the output signal is 2 V, while the output noise is 0.4 V. The noise figure of receiver isa)2b)0.5c)0.2d)None of the mentionedCorrect answer is option 'A'. Can you explain this answer?
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