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Which is correct order of bond angle:
  • a)
    CCl4 > BF3 > NO2+
  • b)
    NH3 > NCl3 > NBr3
  • c)
    Br2O > Cl2O > OF2
  • d)
    PCl3 > PBr3 > PI3
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Which is correct order of bond angle:a)CCl4 > BF3 > NO2+b)NH3 ...
The correct order of bond angle is determined by the repulsion between the bonding pairs and lone pairs of electrons present in the molecule. The greater the repulsion, the larger the bond angle. Let's analyze the given options to determine the correct order of bond angle.

a) CCl4, BF3, NO2
- CCl4 has a tetrahedral geometry with bond angle of 109.5°.
- BF3 has a trigonal planar geometry with bond angle of 120°.
- NO2 has a bent geometry with bond angle of 115°.

Therefore, the correct order of bond angle for option a) is: BF3 > NO2 > CCl4.

b) NH3, NCl3, NBr3
- NH3 has a trigonal pyramidal geometry with bond angle of 107°.
- NCl3 has a trigonal pyramidal geometry with bond angle of 107°.
- NBr3 has a trigonal pyramidal geometry with bond angle of 102°.

Therefore, the correct order of bond angle for option b) is: NH3 = NCl3 > NBr3.

c) Br2O, Cl2O, OF2
- Br2O has a bent geometry with bond angle of 110°.
- Cl2O has a bent geometry with bond angle of 111°.
- OF2 has a bent geometry with bond angle of 103°.

Therefore, the correct order of bond angle for option c) is: Cl2O > Br2O > OF2.

d) PCl3, PBr3, PI3
- PCl3 has a trigonal pyramidal geometry with bond angle of 107°.
- PBr3 has a trigonal pyramidal geometry with bond angle of 107°.
- PI3 has a trigonal pyramidal geometry with bond angle of 102°.

Therefore, the correct order of bond angle for option d) is: PCl3 = PBr3 > PI3.

Hence, the correct order of bond angle among the given options is c) Cl2O > Br2O > OF2.
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Community Answer
Which is correct order of bond angle:a)CCl4 > BF3 > NO2+b)NH3 ...
F being small in size have small bond angle as lone pair lone pair repulsion dec it... But in case of Cl, Br they are large in size and overcome that lone pair - lone pair repulsion. Br is larger than Cl so repulsion between these(br) will be greater thus bond angle of OBr2 is greater than OCl2
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