A car moving at a speed of 108km/h. the driver of the car suddenly fin...
Analysis of the situation
The situation can be analyzed using the following parameters:
- Initial velocity of the car = 108 km/h
- Distance of the puppy from the car = 100 m
- Retardation produced by the brakes = 5 m/s^2
- Reaction time of the driver = 0.2 s
Calculation of stopping distance
The stopping distance of the car can be calculated as follows:
Initial velocity of the car, v = 108 km/h = 30 m/s
Acceleration produced by the brakes, a = -5 m/s^2 (negative because it is a retardation)
Reaction time of the driver, t = 0.2 s
Distance covered during the reaction time, s1 = vt = 30 x 0.2 = 6 m
Final velocity of the car, v1 = 0 m/s (because the car has to stop)
Using the equation, v^2 - v1^2 = 2as, we get:
s = (v^2 - v1^2)/2a + s1 = (30^2 - 0)/2(-5) + 6 = 36 m
Conclusion
The stopping distance of the car is calculated to be 36 m. As this distance is greater than the distance of the puppy from the car (100 m), the driver will not be able to save the puppy even if he applies the brakes as soon as he sees the puppy. Therefore, the driver will not be able to save the puppy. It is important to note that the driver's reaction time plays a crucial role in such situations and it is always better to drive at a safe speed to avoid such accidents.