The shape and expected hybridization of BrO3- and HOCl are:a)BrO3- pyr...
Shape and Hybridization of BrO3- and HOCl
BrO3-:
- The central atom is Br, which has 7 valence electrons.
- There are 3 oxygen atoms bonded to Br, which contribute 3x6=18 valence electrons.
- The overall charge of the ion is -1, so there is an extra electron.
- To determine the hybridization, we need to know the number of electron pairs around the central atom, which is 4 (3 from the O atoms and 1 extra).
- The hybridization is sp3 (4 electron pairs).
HOCl:
- The central atom is O, which has 6 valence electrons.
- There is 1 Cl atom and 1 H atom bonded to O, which contribute 7 valence electrons.
- To determine the hybridization, we need to know the number of electron pairs around the central atom, which is 3 (1 from Cl, 1 from H, and 1 lone pair on O).
- The hybridization is sp2 (3 electron pairs).
Overall, the shape and expected hybridization of BrO3- is trigonal pyramidal (3 bonded atoms and 1 lone pair) with sp3 hybridization, while the shape and expected hybridization of HOCl is bent/angular (2 bonded atoms and 1 lone pair) with sp2 hybridization. Therefore, the correct answer is option D.
The shape and expected hybridization of BrO3- and HOCl are:a)BrO3- pyr...
In BrO3 - central metal atom is 'Br' and it has 3 -sigma bond and 1- lone pair present ,therefore it has sp3 hybridisation and trigonal shape and in 'HOCl' central metal atom is 'O' and it has 2- sigma bond and 2-lone pair therefore it has Sp3 hybridisation and angular shape.