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For a normal distribution having mean=2 and variance=4,Fourth central movement u4 is Ans 48?
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For a normal distribution having mean=2 and variance=4,Fourth central ...
Calculation of Fourth Central Moment (u4) for Normal Distribution




To calculate the fourth central moment (u4) for a normal distribution having mean=2 and variance=4, we can use the formula:

u4 = E[(X-μ)^4]

where, X is the random variable, μ is the mean, and E[.] denotes the expected value.



Step-by-Step Solution:

  • Firstly, we need to find the standard deviation of the normal distribution, which is the square root of variance. So, the standard deviation is sqrt(4) = 2.

  • Next, we can use the formula for the fourth central moment:

    u4 = E[(X-μ)^4]

    = E[(X-2)^4]


  • As the distribution is normal, we know that the central moments of odd order are zero. So, we only need to consider the even order moments.

    u4 = E[(X-2)^4]

    = E[X^4 - 8X^3 + 24X^2 - 32X + 16]

    = E[X^4] - 8E[X^3] + 24E[X^2] - 32E[X] + 16


  • Now, we can use the properties of the standard normal distribution to find the values of E[X^4], E[X^3], E[X^2], and E[X].

    E[X] = μ = 2

    E[X^2] = μ^2 + σ^2 = 2^2 + 2^2 = 8

    E[X^3] = 0 (as the distribution is symmetric)

    E[X^4] = 3σ^4 + 6μ^2σ^2 + μ^4 = 3(2^4) + 6(2^2)(2^2) + 2^4 = 48


  • Substituting these values in the formula for u4:

    u4 = E[X^4] - 8E[X^3] + 24E[X^2] - 32E[X] + 16

    = 48 - 0 + 24(8) - 32(2) + 16

    = 48



Therefore, the fourth central moment (u4) for the given normal distribution is 48.
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For a normal distribution having mean=2 and variance=4,Fourth central movement u4 is Ans 48?
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