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An ideal gas occupying a volume of 2dm3 at a pressure of 5 bar undergoes isothermal and irreversible
expansion against external pressure of 1 bar. The final volume of the system and the work involved in the
process is
  • a)
    10 dm3, 1000 J
  • b)
    10 dm3, –1000 J
  • c)
    8 dm3, –800 J
  • d)
    10 dm3, –800 J
Correct answer is option 'C'. Can you explain this answer?
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The ideal gas law states that PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the ideal gas constant, and T is temperature.

Since the process is isothermal, the temperature remains constant. Therefore, we can rewrite the ideal gas law as:

P1V1 = P2V2

where P1 is the initial pressure, V1 is the initial volume, P2 is the final pressure, and V2 is the final volume.

Given:
P1 = 5 bar
V1 = 2 dm^3
P2 = 1 bar (external pressure)
V2 = ?

Using the given values in the equation, we can solve for V2:

5 bar * 2 dm^3 = 1 bar * V2
10 dm^3 = V2

Therefore, the final volume of the system is 10 dm^3 (option a).

Now let's calculate the work involved in the process. The work done by the gas during expansion can be calculated using the formula:

Work = -Pext * (V2 - V1)

where Pext is the external pressure.

Plugging in the values, we get:

Work = -1 bar * (10 dm^3 - 2 dm^3)
Work = -1 bar * 8 dm^3

Since the pressure is in bar and the volume is in dm^3, we need to convert the units to joules (J) using the conversion factor:

1 bar * 1 dm^3 = 100 J

Therefore, the work involved in the process is:

Work = -1 bar * 8 dm^3 * 100 J/bar.dm^3
Work = -800 J

Since the work is negative, it means that work is done on the system (external work) during the expansion process.

Therefore, the final volume of the system is 10 dm^3 and the work involved in the process is -800 J (option b).
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An ideal gas occupying a volume of 2dm3 at a pressure of 5 bar undergoes isothermal and irreversibleexpansion against external pressure of 1 bar. The final volume of the system and the work involved in theprocess isa)10 dm3, 1000 Jb)10 dm3, –1000 Jc)8 dm3, –800 Jd)10 dm3, –800 JCorrect answer is option 'C'. Can you explain this answer?
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An ideal gas occupying a volume of 2dm3 at a pressure of 5 bar undergoes isothermal and irreversibleexpansion against external pressure of 1 bar. The final volume of the system and the work involved in theprocess isa)10 dm3, 1000 Jb)10 dm3, –1000 Jc)8 dm3, –800 Jd)10 dm3, –800 JCorrect answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about An ideal gas occupying a volume of 2dm3 at a pressure of 5 bar undergoes isothermal and irreversibleexpansion against external pressure of 1 bar. The final volume of the system and the work involved in theprocess isa)10 dm3, 1000 Jb)10 dm3, –1000 Jc)8 dm3, –800 Jd)10 dm3, –800 JCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An ideal gas occupying a volume of 2dm3 at a pressure of 5 bar undergoes isothermal and irreversibleexpansion against external pressure of 1 bar. The final volume of the system and the work involved in theprocess isa)10 dm3, 1000 Jb)10 dm3, –1000 Jc)8 dm3, –800 Jd)10 dm3, –800 JCorrect answer is option 'C'. Can you explain this answer?.
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