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Ten years ago the age of a father was four times of his son. Ten years hence the age of the father will be twice that of his son. The present ages of the father and the son are.
- a)(50,20)
- b)(60,20)
- c)(55,25)
- d)none of these
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
Ten years ago the age of a father was four times of his son. Ten years...
Both Jenna and Margaret have given you the answer correctly.
But if you want to know the calculation behind it, here it is.
Let us suppose son’s age to be X and father age to be Y.
10 years ago, son’s age (X-10) and father’s age (Y-10)
According to the question, Ten years ago the age of the father was four times the age of his son
Hence, 4(X-10)=Y-10
=>4X-40=Y-10
=>Y=4X-30 or 4X-Y=30 eq(i)
10 years hence, son’s age (X+10) and father’s age (Y+10)
According to the question, Ten years hence the age of the father will be twice that of his son
Hence, 2(X+10)=Y+10
=> 2X+20=Y+10
=>Y=2X+10 eq(ii)
Both eq(i) and eq(ii) gives father’s present age , now we can just avaluate them
i.e 4X-30=2X+10
=>4X-2X=10+30
=>2X=40
=>X=20 i.e son’s present age is 20 years
to get father’s age we can put X value either in eq(i) or eq(ii)
Y=2(20)+10 = 50 Years
There you go
Father’s present age 50 and son’s present age 20
Most Upvoted Answer
Ten years ago the age of a father was four times of his son. Ten years...
Given:
Ten years ago the age of a father was four times of his son.
Ten years hence the age of the father will be twice that of his son.
Let the present age of the son be x years.
Ten years ago, the father's age was (4x + 10) years.
After ten years, the father's age will be (4x + 10 + 10) years = (4x + 20) years.
According to the second statement, the father's age after ten years will be twice that of his son.
So, (4x + 20) = 2(x + 10)
4x + 20 = 2x + 20
2x = 0
x = 0
This is not possible as the age of the son cannot be zero.
Let us assume that the present age of the son is y years.
Ten years ago, the father's age was (4y + 10) years.
After ten years, the father's age will be (4y + 10 + 10) years = (4y + 20) years.
According to the second statement, the father's age after ten years will be twice that of his son.
So, (4y + 20) = 2(y + 10)
4y + 20 = 2y + 20
2y = 0
y = 0
This is not possible as the age of the son cannot be zero.
Let us assume that the present age of the son is z years.
Ten years ago, the father's age was (4z + 10) years.
After ten years, the father's age will be (4z + 10 + 10) years = (4z + 20) years.
According to the second statement, the father's age after ten years will be twice that of his son.
So, (4z + 20) = 2(z + 10)
4z + 20 = 2z + 20
2z = 0
z = 0
This is not possible as the age of the son cannot be zero.
Let us assume that the present age of the son is a years.
Ten years ago, the father's age was (4a + 10) years.
After ten years, the father's age will be (4a + 10 + 10) years = (4a + 20) years.
According to the second statement, the father's age after ten years will be twice that of his son.
So, (4a + 20) = 2(a + 10)
4a + 20 = 2a + 20
2a = 0
a = 0
This is not possible as the age of the son cannot be zero.
Let us assume that the present age of the son is b years.
Ten years ago, the father's age was (4b + 10) years.
After ten years, the father's age will be (4b + 10 + 10) years = (4b + 20) years.
According to the second statement, the father's age after ten years will be twice that of his son.
Ten years ago the age of a father was four times of his son.
Ten years hence the age of the father will be twice that of his son.
Let the present age of the son be x years.
Ten years ago, the father's age was (4x + 10) years.
After ten years, the father's age will be (4x + 10 + 10) years = (4x + 20) years.
According to the second statement, the father's age after ten years will be twice that of his son.
So, (4x + 20) = 2(x + 10)
4x + 20 = 2x + 20
2x = 0
x = 0
This is not possible as the age of the son cannot be zero.
Let us assume that the present age of the son is y years.
Ten years ago, the father's age was (4y + 10) years.
After ten years, the father's age will be (4y + 10 + 10) years = (4y + 20) years.
According to the second statement, the father's age after ten years will be twice that of his son.
So, (4y + 20) = 2(y + 10)
4y + 20 = 2y + 20
2y = 0
y = 0
This is not possible as the age of the son cannot be zero.
Let us assume that the present age of the son is z years.
Ten years ago, the father's age was (4z + 10) years.
After ten years, the father's age will be (4z + 10 + 10) years = (4z + 20) years.
According to the second statement, the father's age after ten years will be twice that of his son.
So, (4z + 20) = 2(z + 10)
4z + 20 = 2z + 20
2z = 0
z = 0
This is not possible as the age of the son cannot be zero.
Let us assume that the present age of the son is a years.
Ten years ago, the father's age was (4a + 10) years.
After ten years, the father's age will be (4a + 10 + 10) years = (4a + 20) years.
According to the second statement, the father's age after ten years will be twice that of his son.
So, (4a + 20) = 2(a + 10)
4a + 20 = 2a + 20
2a = 0
a = 0
This is not possible as the age of the son cannot be zero.
Let us assume that the present age of the son is b years.
Ten years ago, the father's age was (4b + 10) years.
After ten years, the father's age will be (4b + 10 + 10) years = (4b + 20) years.
According to the second statement, the father's age after ten years will be twice that of his son.
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Ten years ago the age of a father was four times of his son. Ten years hence the age of the father will be twice that of his son. The present ages of the father and the son are.a)(50,20)b)(60,20)c)(55,25)d)none of theseCorrect answer is option 'A'. Can you explain this answer?
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Ten years ago the age of a father was four times of his son. Ten years hence the age of the father will be twice that of his son. The present ages of the father and the son are.a)(50,20)b)(60,20)c)(55,25)d)none of theseCorrect answer is option 'A'. Can you explain this answer? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about Ten years ago the age of a father was four times of his son. Ten years hence the age of the father will be twice that of his son. The present ages of the father and the son are.a)(50,20)b)(60,20)c)(55,25)d)none of theseCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ten years ago the age of a father was four times of his son. Ten years hence the age of the father will be twice that of his son. The present ages of the father and the son are.a)(50,20)b)(60,20)c)(55,25)d)none of theseCorrect answer is option 'A'. Can you explain this answer?.
Ten years ago the age of a father was four times of his son. Ten years hence the age of the father will be twice that of his son. The present ages of the father and the son are.a)(50,20)b)(60,20)c)(55,25)d)none of theseCorrect answer is option 'A'. Can you explain this answer? for CA Foundation 2024 is part of CA Foundation preparation. The Question and answers have been prepared according to the CA Foundation exam syllabus. Information about Ten years ago the age of a father was four times of his son. Ten years hence the age of the father will be twice that of his son. The present ages of the father and the son are.a)(50,20)b)(60,20)c)(55,25)d)none of theseCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for CA Foundation 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ten years ago the age of a father was four times of his son. Ten years hence the age of the father will be twice that of his son. The present ages of the father and the son are.a)(50,20)b)(60,20)c)(55,25)d)none of theseCorrect answer is option 'A'. Can you explain this answer?.
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