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The heat of neutralization of a strong acid and a strong alkali is 57.0 KJ mol–1. The heat released when 0.5 mole of HNO3 solution is mixed with 0.2 mole of KOH is:
- a)57.0 KJ
- b)11.4 KJ
- c)28.5 KJ
- d)34.9 KJ
Correct answer is option 'B'. Can you explain this answer?
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The heat of neutralization of a strong acid and a strong alkali is 57....
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The heat of neutralization of a strong acid and a strong alkali is 57....
Given: Heat of neutralization = 57.0 KJ/mol
Moles of HNO3 solution = 0.5 mol
Moles of KOH = 0.2 mol
To find: Heat released when HNO3 solution is mixed with KOH
Formula: Heat released = n x Heat of neutralization
where n is the number of moles of the limiting reactant.
Calculation:
From the balanced chemical equation:
HNO3 + KOH → KNO3 + H2O
It is clear that 1 mole of HNO3 reacts with 1 mole of KOH to produce 1 mole of water. Therefore, 0.2 mol of KOH will react completely with 0.2 mol of HNO3, and 0.3 mol of HNO3 will be left unreacted.
Since HNO3 is the limiting reactant, the heat released will be calculated using the following formula:
Heat released = n x Heat of neutralization
where n is the number of moles of HNO3 that reacts.
n = 0.2 mol (moles of KOH used)
Therefore, Heat released = 0.2 mol x 57.0 KJ/mol = 11.4 KJ
Hence, the correct answer is option B, 11.4 KJ.
Moles of HNO3 solution = 0.5 mol
Moles of KOH = 0.2 mol
To find: Heat released when HNO3 solution is mixed with KOH
Formula: Heat released = n x Heat of neutralization
where n is the number of moles of the limiting reactant.
Calculation:
From the balanced chemical equation:
HNO3 + KOH → KNO3 + H2O
It is clear that 1 mole of HNO3 reacts with 1 mole of KOH to produce 1 mole of water. Therefore, 0.2 mol of KOH will react completely with 0.2 mol of HNO3, and 0.3 mol of HNO3 will be left unreacted.
Since HNO3 is the limiting reactant, the heat released will be calculated using the following formula:
Heat released = n x Heat of neutralization
where n is the number of moles of HNO3 that reacts.
n = 0.2 mol (moles of KOH used)
Therefore, Heat released = 0.2 mol x 57.0 KJ/mol = 11.4 KJ
Hence, the correct answer is option B, 11.4 KJ.
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The heat of neutralization of a strong acid and a strong alkali is 57.0 KJ mol–1. The heat released when 0.5 mole of HNO3 solution is mixed with 0.2 mole of KOH is:a)57.0 KJ b)11.4 KJ c)28.5 KJ d)34.9 KJCorrect answer is option 'B'. Can you explain this answer?
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The heat of neutralization of a strong acid and a strong alkali is 57.0 KJ mol–1. The heat released when 0.5 mole of HNO3 solution is mixed with 0.2 mole of KOH is:a)57.0 KJ b)11.4 KJ c)28.5 KJ d)34.9 KJCorrect answer is option 'B'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The heat of neutralization of a strong acid and a strong alkali is 57.0 KJ mol–1. The heat released when 0.5 mole of HNO3 solution is mixed with 0.2 mole of KOH is:a)57.0 KJ b)11.4 KJ c)28.5 KJ d)34.9 KJCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The heat of neutralization of a strong acid and a strong alkali is 57.0 KJ mol–1. The heat released when 0.5 mole of HNO3 solution is mixed with 0.2 mole of KOH is:a)57.0 KJ b)11.4 KJ c)28.5 KJ d)34.9 KJCorrect answer is option 'B'. Can you explain this answer?.
The heat of neutralization of a strong acid and a strong alkali is 57.0 KJ mol–1. The heat released when 0.5 mole of HNO3 solution is mixed with 0.2 mole of KOH is:a)57.0 KJ b)11.4 KJ c)28.5 KJ d)34.9 KJCorrect answer is option 'B'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The heat of neutralization of a strong acid and a strong alkali is 57.0 KJ mol–1. The heat released when 0.5 mole of HNO3 solution is mixed with 0.2 mole of KOH is:a)57.0 KJ b)11.4 KJ c)28.5 KJ d)34.9 KJCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The heat of neutralization of a strong acid and a strong alkali is 57.0 KJ mol–1. The heat released when 0.5 mole of HNO3 solution is mixed with 0.2 mole of KOH is:a)57.0 KJ b)11.4 KJ c)28.5 KJ d)34.9 KJCorrect answer is option 'B'. Can you explain this answer?.
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