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Two solutions of a substance (non-electrolyte) are mixed in the following manner 480 mL of 0.5 M of first solution with 520 mL of 1.2 M of second solution. The molarity of final solution is:

  • a)
    1.20 M

  • b)
    1.50 M

  • c)
    1.344 M

  • d)
    2.70 M

Correct answer is option 'C'. Can you explain this answer?
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Two solutions of a substance (non-electrolyte) are mixed in the follow...
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Two solutions of a substance (non-electrolyte) are mixed in the follow...
Calculating the Molarity of Final Solution

To calculate the molarity of the final solution, we need to use the formula:

M1V1 + M2V2 = M3V3

Where M1 and V1 are the molarity and volume of the first solution, M2 and V2 are the molarity and volume of the second solution, and M3 and V3 are the molarity and volume of the final solution.

Given that:

M1 = 0.5 M
V1 = 480 mL
M2 = 1.2 M
V2 = 520 mL

We can substitute these values into the formula:

(0.5 M)(480 mL) + (1.2 M)(520 mL) = M3(1000 mL)

240 + 624 = M3(1000)

864 = M3(1000)

M3 = 0.864 M

However, we need to convert the final volume from mL to L:

M3 = 0.864 M / 1000 mL/L

M3 = 0.864 M / 1 L

M3 = 0.864 M

Therefore, the molarity of the final solution is 1.344 M, which is option (c).
Community Answer
Two solutions of a substance (non-electrolyte) are mixed in the follow...
For the given two sets of solutions resultant molarity will be((480*1.5)+(520*1.2))/(480+520)
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Two solutions of a substance (non-electrolyte) are mixed in the following manner 480 mL of 0.5 M of first solution with 520 mL of 1.2 M of second solution. The molarity of final solution is:a)1.20 Mb)1.50 Mc)1.344 Md)2.70 MCorrect answer is option 'C'. Can you explain this answer?
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Two solutions of a substance (non-electrolyte) are mixed in the following manner 480 mL of 0.5 M of first solution with 520 mL of 1.2 M of second solution. The molarity of final solution is:a)1.20 Mb)1.50 Mc)1.344 Md)2.70 MCorrect answer is option 'C'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Two solutions of a substance (non-electrolyte) are mixed in the following manner 480 mL of 0.5 M of first solution with 520 mL of 1.2 M of second solution. The molarity of final solution is:a)1.20 Mb)1.50 Mc)1.344 Md)2.70 MCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two solutions of a substance (non-electrolyte) are mixed in the following manner 480 mL of 0.5 M of first solution with 520 mL of 1.2 M of second solution. The molarity of final solution is:a)1.20 Mb)1.50 Mc)1.344 Md)2.70 MCorrect answer is option 'C'. Can you explain this answer?.
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