A hydrogen contain 90% of carbon and 10% hydrogen. The empirical formu...
Given C 90%, H10%.
So Moles of element C = 90/12 =7.5
So Moles of element H = 10/1 =10
Simplest molar ration of carbon= 7.5/7.5=1
Simplest molar ration of H= 10/7.5=1.33
whole no ratio element C= 1*3=3
whole no ratio element H= 1.33*3=4
so its C3H4
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A hydrogen contain 90% of carbon and 10% hydrogen. The empirical formu...
Let us take the mass of compound =100 gm
Moles of carbon =
12
90
=7.5
Moles of hydrogen =
1
10
=10
The ratio of C:H=7.5:10
=3:4
∴ Empirical formula =C
3
H
4
.
Hence, option C is correct.
A hydrogen contain 90% of carbon and 10% hydrogen. The empirical formu...
Empirical Formula Calculation:
The empirical formula of a compound represents the simplest ratio of the elements present in it. To determine the empirical formula, we need to convert the given percentages of carbon and hydrogen into moles and find their ratio.
1. Convert percentages into grams:
Assuming we have 100g of the compound, 90% of carbon corresponds to 90g, and 10% of hydrogen corresponds to 10g.
2. Convert grams into moles:
To convert grams into moles, we divide the given mass by the molar mass of each element. The molar mass of carbon is 12g/mol, and the molar mass of hydrogen is 1g/mol.
- Moles of carbon (C): 90g / 12g/mol = 7.5 mol
- Moles of hydrogen (H): 10g / 1g/mol = 10 mol
3. Find the simplest ratio:
To find the simplest ratio between carbon and hydrogen, we divide the number of moles of each element by the smallest number of moles obtained.
- Moles of carbon (C): 7.5 mol / 7.5 mol = 1 mol
- Moles of hydrogen (H): 10 mol / 7.5 mol ≈ 1.33 mol
Since we need to find the whole number ratio, we multiply the moles of carbon and hydrogen by an appropriate factor to obtain whole numbers.
- Moles of carbon (C): 1 mol × 3 = 3 mol
- Moles of hydrogen (H): 1.33 mol × 3 ≈ 4 mol
Therefore, the empirical formula of the compound is C3H4, which corresponds to option 'C' in the given choices.
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