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Direction (Q. Nos. 1 - 8) This section contains 8 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE option is correct.


Q. How many different alkenes are formed when 2 -chlorobutane is treated with ethanolic solution of KOH? 

  • a)
    1

  • b)
    3

  • c)
    2

  • d)
    4

Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Direction (Q. Nos. 1 - 8) This section contains 8 multiple choice ques...
With ethanolic KOH, we have E2 elimination.



So, we have 3 products in all
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Direction (Q. Nos. 1 - 8) This section contains 8 multiple choice ques...
The reaction of 2-chlorobutane with ethanolic solution of KOH is an example of an elimination reaction known as dehydrohalogenation. In this reaction, a hydrogen atom and a halogen atom are removed from adjacent carbon atoms to form a double bond.

The possible alkenes that can be formed are:

1. Butene
2. But-2-ene
3. But-1-ene
4. Isobutene

The number of different alkenes formed depends on the position of the double bond. In the case of 2-chlorobutane, the chlorine atom is attached to the second carbon atom, so the double bond can form between the first and second carbon atoms or between the second and third carbon atoms.

Hence, the correct answer is option (b) 2.
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Community Answer
Direction (Q. Nos. 1 - 8) This section contains 8 multiple choice ques...
C is the correct answer because when 2 chlorobutanes treated with ethanolic solution of koh it forms 2 alkenes and loss 2 chlorins
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Direction (Q. Nos. 1 - 8) This section contains 8 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE option is correct.Q.How many different alkenes are formed when 2 -chlorobutane is treated with ethanolic solution of KOH?a)1b)3c)2d)4Correct answer is option 'B'. Can you explain this answer?
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