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Current I1, I2 and I3 meet at a junction (node) in a circuit. All currents are marked as entering the node. If I1=-6sin(wt) mA and I2=8cos(wt) mA, then I3 will be? a) 10 cos(wt 36.87) mAb) 14 cos(wt 36.87) mA c) -14 sin(wt 36.87) mA d) -10 cos(wt 36.87) mA Correct answer is option d.? for Electronics and Communication Engineering (ECE) 2024 is part of Electronics and Communication Engineering (ECE) preparation. The Question and answers have been prepared according to the Electronics and Communication Engineering (ECE) exam syllabus. Information about Current I1, I2 and I3 meet at a junction (node) in a circuit. All currents are marked as entering the node. If I1=-6sin(wt) mA and I2=8cos(wt) mA, then I3 will be? a) 10 cos(wt 36.87) mAb) 14 cos(wt 36.87) mA c) -14 sin(wt 36.87) mA d) -10 cos(wt 36.87) mA Correct answer is option d.? covers all topics & solutions for Electronics and Communication Engineering (ECE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Current I1, I2 and I3 meet at a junction (node) in a circuit. All currents are marked as entering the node. If I1=-6sin(wt) mA and I2=8cos(wt) mA, then I3 will be? a) 10 cos(wt 36.87) mAb) 14 cos(wt 36.87) mA c) -14 sin(wt 36.87) mA d) -10 cos(wt 36.87) mA Correct answer is option d.?.

Solutions for Current I1, I2 and I3 meet at a junction (node) in a circuit. All currents are marked as entering the node. If I1=-6sin(wt) mA and I2=8cos(wt) mA, then I3 will be? a) 10 cos(wt 36.87) mAb) 14 cos(wt 36.87) mA c) -14 sin(wt 36.87) mA d) -10 cos(wt 36.87) mA Correct answer is option d.? in English & in Hindi are available as part of our courses for Electronics and Communication Engineering (ECE). Download more important topics, notes, lectures and mock test series for Electronics and Communication Engineering (ECE) Exam by signing up for free.

Here you can find the meaning of Current I1, I2 and I3 meet at a junction (node) in a circuit. All currents are marked as entering the node. If I1=-6sin(wt) mA and I2=8cos(wt) mA, then I3 will be? a) 10 cos(wt 36.87) mAb) 14 cos(wt 36.87) mA c) -14 sin(wt 36.87) mA d) -10 cos(wt 36.87) mA Correct answer is option d.? defined & explained in the simplest way possible. Besides giving the explanation of Current I1, I2 and I3 meet at a junction (node) in a circuit. All currents are marked as entering the node. If I1=-6sin(wt) mA and I2=8cos(wt) mA, then I3 will be? a) 10 cos(wt 36.87) mAb) 14 cos(wt 36.87) mA c) -14 sin(wt 36.87) mA d) -10 cos(wt 36.87) mA Correct answer is option d.?, a detailed solution for Current I1, I2 and I3 meet at a junction (node) in a circuit. All currents are marked as entering the node. If I1=-6sin(wt) mA and I2=8cos(wt) mA, then I3 will be? a) 10 cos(wt 36.87) mAb) 14 cos(wt 36.87) mA c) -14 sin(wt 36.87) mA d) -10 cos(wt 36.87) mA Correct answer is option d.? has been provided alongside types of Current I1, I2 and I3 meet at a junction (node) in a circuit. All currents are marked as entering the node. If I1=-6sin(wt) mA and I2=8cos(wt) mA, then I3 will be? a) 10 cos(wt 36.87) mAb) 14 cos(wt 36.87) mA c) -14 sin(wt 36.87) mA d) -10 cos(wt 36.87) mA Correct answer is option d.? theory, EduRev gives you an ample number of questions to practice Current I1, I2 and I3 meet at a junction (node) in a circuit. All currents are marked as entering the node. If I1=-6sin(wt) mA and I2=8cos(wt) mA, then I3 will be? a) 10 cos(wt 36.87) mAb) 14 cos(wt 36.87) mA c) -14 sin(wt 36.87) mA d) -10 cos(wt 36.87) mA Correct answer is option d.? tests, examples and also practice Electronics and Communication Engineering (ECE) tests.