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The critical angle for total internal reflection at a liquid–air interface is 42.5∘ If a ray of light traveling in air has an angle of incidence at the interface of 35∘ what angle does the refracted ray in the liquid make with the normal?
- a)25.8∘
- b)24.8∘
- c)22.8∘
- d)23.8∘
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
The critical angle for total internal reflection at a liquid–air...
μ = 1/sin 42.5
a) required r1 = arc sin[(sin 35)/(sin 42.5)] = 58.1Digree
b) required r2 = arc sin[(sin 35)*(sin 42.5)] = 22.8Digree
c. In case of a) bends away from normal, in case of b) bends towards normal
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The critical angle for total internal reflection at a liquid–air...
-air interface is determined by the refractive indices of the two media. The critical angle is defined as the angle of incidence at which the refracted angle of the light ray inside the liquid becomes 90 degrees with respect to the normal to the interface. At this angle of incidence, the refracted angle becomes so large that the light ray is reflected back into the liquid, rather than passing into the air.
The critical angle can be calculated using Snell's law, which relates the angle of incidence to the angle of refraction. For a liquid-air interface, the critical angle is given by:
sin(critical angle) = n_air / n_liquid
where n_air is the refractive index of air (approximately 1) and n_liquid is the refractive index of the liquid. If the angle of incidence is greater than the critical angle, then total internal reflection occurs and the light ray is reflected back into the liquid.
The critical angle can be calculated using Snell's law, which relates the angle of incidence to the angle of refraction. For a liquid-air interface, the critical angle is given by:
sin(critical angle) = n_air / n_liquid
where n_air is the refractive index of air (approximately 1) and n_liquid is the refractive index of the liquid. If the angle of incidence is greater than the critical angle, then total internal reflection occurs and the light ray is reflected back into the liquid.
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The critical angle for total internal reflection at a liquid–air interface is 42.5∘ If a ray of light traveling in air has an angle of incidence at the interface of 35∘what angle does the refracted ray in the liquid make with the normal?a)25.8∘b)24.8∘c)22.8∘d)23.8∘Correct answer is option 'C'. Can you explain this answer?
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