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 A 2-port network is driven by a source Vs = 100 V in series with 5 ohm, and terminated in a 25 ohm resistor. The impedance parameters are

The Thevenin equivalent circuit presented to the 25 ohm resistor is
  • a)
    80 V, 2.8 ohm
  • b)
    160 V, 6.8 ohm
  • c)
     100 V, 2.4 ohm
  • d)
    120 V, 6.4 ohm
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A 2-port network is driven by a source Vs = 100 V in series with 5...
100 = 25I1 + 2I2, V2 = 40I1 + 10I2
Also V2 = 160I1 + 6.8I2
using above equations we get, Vth = 160 V and Rth = 6.8 ohm.
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A 2-port network is driven by a source Vs = 100 V in series with 5...
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A 2-port network is driven by a source Vs = 100 V in series with 5 ohm, and terminated in a 25 ohm resistor. The impedance parameters areThe Thevenin equivalent circuit presented to the 25 ohm resistor isa)80 V, 2.8 ohmb)160 V, 6.8 ohmc)100 V, 2.4 ohmd)120 V, 6.4 ohmCorrect answer is option 'B'. Can you explain this answer?
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A 2-port network is driven by a source Vs = 100 V in series with 5 ohm, and terminated in a 25 ohm resistor. The impedance parameters areThe Thevenin equivalent circuit presented to the 25 ohm resistor isa)80 V, 2.8 ohmb)160 V, 6.8 ohmc)100 V, 2.4 ohmd)120 V, 6.4 ohmCorrect answer is option 'B'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 2-port network is driven by a source Vs = 100 V in series with 5 ohm, and terminated in a 25 ohm resistor. The impedance parameters areThe Thevenin equivalent circuit presented to the 25 ohm resistor isa)80 V, 2.8 ohmb)160 V, 6.8 ohmc)100 V, 2.4 ohmd)120 V, 6.4 ohmCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 2-port network is driven by a source Vs = 100 V in series with 5 ohm, and terminated in a 25 ohm resistor. The impedance parameters areThe Thevenin equivalent circuit presented to the 25 ohm resistor isa)80 V, 2.8 ohmb)160 V, 6.8 ohmc)100 V, 2.4 ohmd)120 V, 6.4 ohmCorrect answer is option 'B'. Can you explain this answer?.
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