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Increasing order of stability among the three main conformations (i.e.. Eclipse, Ami, Gauche) of 2-fluoroethanol is  

  • a)
    Eclipse, Anti, Gauche

  • b)
    Gauche, Eclipse, Anti

  • c)
    Eclipse, Gauche, Anti

  • d)
    Anti, Gauche, Eclipse

Correct answer is option 'C'. Can you explain this answer?
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Increasing order of stability among the three main conformations (i.e....
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Increasing order of stability among the three main conformations (i.e....
**Explanation:**

The stability of conformations in 2-fluoroethanol can be determined based on the interaction between the various atoms and groups present in the molecule.

**1. Eclipse Conformation:**
In the eclipse conformation, the hydrogen atom on the carbon adjacent to the fluorine atom is directly in line with the fluorine atom. This creates a repulsive interaction between the two atoms, leading to increased steric strain. As a result, the eclipse conformation is the least stable among the three conformations.

**2. Anti Conformation:**
In the anti conformation, the hydrogen atom on the carbon adjacent to the fluorine atom is positioned directly opposite to the fluorine atom. This arrangement minimizes the steric repulsion between the two atoms, making the anti conformation more stable than the eclipse conformation.

**3. Gauche Conformation:**
In the gauche conformation, the hydrogen atom on the carbon adjacent to the fluorine atom is positioned approximately 60 degrees away from the fluorine atom. This arrangement creates a moderate steric repulsion between the two atoms, making the gauche conformation less stable than the anti conformation but more stable than the eclipse conformation.

Based on the above explanations, the order of stability among the three conformations is as follows:

1. Eclipse conformation (least stable)
2. Anti conformation
3. Gauche conformation (most stable)

Therefore, the correct answer is option **c) Eclipse, Anti, Gauche**.
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